a. S-1 is true and S-2 is false
b. S-1 is false and S-2 is true
c. Both are false
d. Both are true
Cupric metaborate (Cu(BO2)2 is blue-green in color and is not colorless, but it does convert into cuprous metaborate in a luminous flame(reducing flame)
2Cu(BO2)2 + C → 2CuBO2 + B2O3 + CO↑
Thus, S-1 is incorrect.
Cuprous metaborate is formed by reacting copper sulphate with boric anhydride in a luminous flame.
CuSO4 + B2O3 → Cu(BO2)2 + SO3↑
Hence, S-2 is also incorrect.