S-1: Colourless cupric metaborate is converted into cuprous metaborate in a luminous flame.

a. S-1 is true and S-2 is false

b. S-1 is false and S-2 is true

c. Both are false

d. Both are true

Answer: (c)

Cupric metaborate (Cu(BO₂)₂ is blue-green in color and is not colorless, but it does convert into cuprous metaborate in a luminous flame(reducing flame)

2Cu(BO2)₂ + C → 2CuBO₂ + B₂O₃ + CO↑

Thus, S-1 is incorrect.

Cuprous metaborate is formed by reacting copper sulphate with boric anhydride in a luminous flame.

CuSO₄ + B₂O₃ → Cu(BO₂)₂ + SO₃↑

Hence, S-2 is also incorrect.