Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

S8 + bOH- → cS2- + sS2O2-3 + H2O. Find the value of c.

Answer: 4

Let us look at the half reactions i.e. oxidation and reduction separately.

Oxidation:

S8 → S2O2-3

S8 + 24OH → 4S2O2-3 + 12H2O +16e ….(1)

Reduction:

S8 → S2-

S8 + 16e → 8S2- ….(2)

Adding both the reactions (1) and (2),

2S8 + 24OH → 4S2O2-3 + 8S2- + 12H2O

Dividing the whole equation by 2,

S8 + 12OH → 2S2O2-3 + 4S2- + 6H2O

So, c = 4

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