1) cosec(sec-1x)
2) cot x
3) π
4) None of these
Answer: (1) cosec(sec-1x)
Solution:
Let cosec-1x = A
cosec A = x
sin A = 1/x
Using the identity sin2A + cos2A = 1,
cos A = [√(x2 – 1)]/x
sec A = x/√(x2 – 1)
Thus, sec(cosec-1x) = sec A = x/√(x2 – 1)
Now let us take sec-1x = B
sec B = x
cos B = 1/x
Therefore, sin B = [√(x2 – 1)]/x
cosec B = x/√(x2 – 1)
cosec(sec-1x) = cosec B = x/√(x2 – 1)
Hence, sec(cosec-1x) = cosec(sec-1x)