Checkout JEE MAINS 2022 Question Paper Analysis : Checkout JEE MAINS 2022 Question Paper Analysis :

Seven chits are numbered 1 to 7. Four chits are drawn one by one with replacement. The probability that the least number appearing on any selected chit is 5, is

Seven chits are numbered 1 to 7. Four chits are drawn one by one with replacement. The probability that the least number appearing on any selected chit is 5, is

1) (3/7)4

2) (6/7)3

3) (5. 4. 3)/73

4) (¾)3

Solution: Option (1) (3/7)4

Total number of cases = 7C1. 7C1 . 7C1 . 7C1

The favourable cases for the given condition is {5, 6, 7}

Hence, total number of favourable cases = 3C1. 3C1 .3C1 . 3C1

Hence, the required probability = 3C1. 3C1 .3C1 . 3C1 / 7C1. 7C1 . 7C1 . 7C1

= (3.3.3.3)/(7.7.7.7)

= 34/74

= (3/7)4.

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