1) 3x – y = 7 and x + 3y = 9
2) x – 3y = 7 and 3x + y = 9
3) x – y = 3 and x + y = 2
4) 2x + y = 7 and x – 2y = 9
Solution:
Given line is x – 2y = 3
=> y = ½ x – 3/2
Here slope, m1 = ½
The required line makes an angle 450 with this line.
So tan 45 = |(m1 – m2)/(1 + m1m2)|
1 = |(1/2 – m2)/(1 + ½ m2)|
2 + m2 = ±(1 – 2m2)
Solving we get m2 = 3 or -1/3
Case 1: when m2 = 3
Equation of line passing through (3,2) and slope 3 is
(y – y1) = m(x – x1)
(y – 2) = 3(x – 3)
y – 3x + 7 = 0
=> 3x – y = 7
Case 2: when m2 = -1/3
Equation of line passing through (3,2) and slope -1/3 is
(y – y1) = m(x – x1)
(y – 2) = -1/3(x – 3)
x + 3y = 9
Hence option (1) is the answer.