The imaginary part of (1+i)2/i(2i-1) is (1) 4/5 (2) 0 (3) 2/5 (4) -(4/5)

Solution:

(1+i)2/i(2i-1) = (1+i)2/(-2-i)

= (1+i)2 (-2+i)/(-2-i)(-2+i)

= (1+i)2 (-2+i)/(4–1)

= (1+i)2 (-2+i)/5

= (1+2i-1)(-2+i)/5

= 2i(-2+i)/5

= (-4i-2)/5

Imaginary part in -4/5 

Hence option (4) is the answer.

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