The ratio of water of crystallization present in Mohr’s salt to that of Potash alum is……..x 10-1?

Solution:

Answer: (2.5)

Potash alum = K2(SO4).Al2(SO4)3.24H2O

Mohr’s salt = (NH4)2Fe(SO4)2.6H2O

Ratio of water molecule = \(\frac{6(From \: Mohr’s\: Salt)}{24(From \: Potash\: Alum)}\) = 0.25 = 2.5 x 10-1

Hence, the correct answer is 2.5

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