1) F, T, F
2) F, F, F
3) T, T, T
4) T, F, F
5) F, F, T
Solution: (5) F, F, T
\(\begin{array}{l}\begin{array}{llllll} \text { p } & \text { q } & r & \sim r & p_{\wedge} q & (p \wedge q) \vee(\sim r) \\ \hline \text { T } & \text { T } & \text { T } & \text { F } & \text { T } & \text { T } \\ \hline \text { T } & \text { T } & \text { F } & \text { T } & \text { T } & \text { T } \\ \hline \text { T } & \text { F } & \text { T } & \text { F } & \text { F } & \text { F } \\ \hline \text { T } & \text { F } & \text { F } & \text { T } & \text { F } & \text { T } \\ \hline \text { F } & \text { T } & \text { T } & \text { F } & \text { F } & \text { F } \\ \hline \text { F } & \text { T } & \text { F } & \text { T } & \text { F } & \text { T } \\ \hline \text { F } & \text { F } & \text { T } & \text { F } & \text { F } & \text { F } \\ \hline \text { F } & \text { F } & \text { F } & \text { T } & \text { F } & \text { T } \\ \hline \end{array}\end{array} \)
Hence, (p ∧ q) ∨ (~ r) has truth value F when truth values of p, q and r are T, F, T or F, T, T or F, F, T respectively.
