(1)
\(\begin{array}{l}\Omega ^{3}\end{array} \)
(2)
\(\begin{array}{l}\Omega ^{2}\end{array} \)
(3)
\(\begin{array}{l}\Omega ^{3} – \Omega\end{array} \)
(4)
\(\begin{array}{l}\Omega\end{array} \)
Solution:
(-1+√(3i))/2 = ω
We know ω3n = 1
(-½)+√(3i)/2)1000 = ω1000
= ω3(333) ω
= ω
Hence option (4) is the answer.
