The value of the expression 3cosec20°-sec20° is equal to
2
2sin20°sin40°
4
4sin20°sin40°
Solve for the given function:
Given trigonometric expression is 3cosec20°-sec20°
∴3cosec20°-sec20°=3sin20°-1cos20°=3cos20°-sin20°cos20°sin20°=432cos20°-12sin20°2cos20°sin20°=4sin60°cos20°-cos60°sin20°sin40°∵sin2A=2sinAcosA=4sin60°-20°sin40°∵sinA-B=sinAcosB-sinBcosA=4sin40°sin40°=4
Hence, option (C) is correct.
The value of the expression ((2)2)2× (33 ÷42) ÷ 32 is equal to: