The value of log2log3.....log1001009998...·21
0
1
2
100!
Explanation for correct option
log2log3.....log1001009998...·21=log2log3.....log999998...·21log100100∵logab=bloga=log2log3.....log999998...·21·1∵logaa=1
Proceeding like this we get
=log2log3321=log221log33∵logab=bloga=log221∵logaa=1=log22=1
Hence, the correct option is optionB
The value of ∫2−2(ax3+bx+c) depends on [MNR 1988; UPSEAT 2000]