CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The value of log2log3.....log1001009998...·21


A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

100!

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

1


Explanation for correct option

log2log3.....log1001009998...·21=log2log3.....log999998...·21log100100logab=bloga=log2log3.....log999998...·21·1logaa=1

Proceeding like this we get

=log2log3321=log221log33logab=bloga=log221logaa=1=log22=1

Hence, the correct option is optionB


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Theorems in Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon