Question

Using a screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

• A. 2.125 cm
• B. 2.124 cm
• C. 2.123
• D. 2.121 cm

Answer 1

The correct option is B

2.124 cm

Step 1 Given data

A screw gauge of pitch 0.1 cm and 50 divisions on its circular scale

Step 2: Formula used

$LeastCount=\frac{Pitch}{Totalnumberofdivisionsinthecircularshape}$

Step 3: Calculating the thickness

The linear distance covered by the screw is inversely proportional to the spin given to it. The screw's linear displacement when turned by one division of the circular scale is the shortest distance that the instrument can accurately measure. The instrument's least count is what it is called.

$LeastCount=\frac{0.1}{50}=0.002$

When we multiply by division no.’s it must be even because L.C. is 0.002.

So, any measurement will be an integral Multiple of LC.

Hence, option B is the correct option.