Question

What is the Hybridization of Octahedral?

Answer 1

1. The octahedral geometry of a molecule is when a central atom is bound with six atoms or six ligands.
2. In octahedral complexes molecule has to make the bond with six atoms so they have one s orbital, three p orbitals, and two d orbitals involve in bond formation.
3. Thus the hybridization of octahedral is ${\mathrm{sp}}^3{\mathrm{d}}^2$.
4. Example-Sulphur Hexafluoride$\left({\mathrm{SF}}_6\right)$has the octahedral geometry where one Sulphur$\left(\mathrm{S}\right)$ atom makes six bonds with Fluorine$\left(\mathrm{F}\right)$.
5. Sulphur uses its one s orbital, three p orbitals, and two d orbitals. Thus has a hybridization ${\mathrm{sp}}^3{\mathrm{d}}^2$.