Question

What is the hybridization of ${\mathrm{SnCl}}_2$?

Answer 1

1. The central atom in ${\mathrm{SnCl}}_2$is $\mathrm{Sn}$.
2. $\mathrm{Sn}$ has atomic number 50. So, the electronic Configuration of $\mathrm{Sn}$is $\left[\mathrm{Kr}\right]5s^{2}4d^{10}5p^2$.

Calculation of hybridization of ${\mathrm{SnCl}}_2$

Formula used

$\mathrm{Steric}\mathrm{number}=\mathrm{lone}\mathrm{pair}+\mathrm{bond}\mathrm{pair}\left(\mathrm{\sigma }\right)$

Lone pair= 1

Bond pair=2

Thus by putting the values in the formula we get

$$\begin{gathered} \mathrm{Steric}\mathrm{number}=1+2 \\ \mathrm{Steric}\mathrm{number}=3 \end{gathered}$$

Thus the Hybridization of ${\mathrm{SnCl}}_2$ is ${\mathrm{sp}}^2$ and shape is trigonal pyramidal.