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Question

Which one of the following relations on R is an equivalence relation?


A

aR1b|a|=|b|

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B

aR2bab

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C

aR3badividesb

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D

aR4ba<b

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Solution

The correct option is A

aR1b|a|=|b|


Explanation for correct option:

Let R be a relation

Reflexive relation: A homogeneous binary relation R on a set X is reflexive if it relates every element of X to itself.

Symmetric relation: a relation R is symmetric only if (b,a)R is true when (a,b)R.

Transitive relation: In transitive relation aRbandbRcaRca,b,cA i.e., (a,b)R and (b,c)R then it implies (a,c)R

Equivalence relation: if a relation satisfies all the conditions of reflexive, symmetric, and transitive relation then we say that the relation has an equivalence relation.

For option (a)

For reflexive it is always true that if (a,a)R1|a|=|a|

For symmetric relation

let (a,b)R1|a|=|b|

|a|=|b|

|b|=|a|

(b,a)R1

This relation satisfies symmetric relation.

For transitive relation

let (a,b)R1and(b,c)R1|a|=|b|andb=c

|a|=c

(a,c)R1

This relation satisfies the transitive relation.

aR1b|a|=|b| satisfies reflexive relation, symmetric relation, and transitive relation.

Hence this expression satisfies the equivalence relation.

Therefore, option (a) is the correct option.

Explanation for incorrect options:

Option (B)

If ab, then ab.

So R2 does not satisfy the symmetric property.

Hence R2 is not an equivalence relation.

Option (C)

adividesb does not imply bdividesa.

So R3 does not satisfy the symmetric property.

Hence R3 is not an equivalence relation.

Option (D)

If a>b, then it does not imply a<b.

So R4 does not satisfy the symmetric property.

Hence R4 is not an equivalence relation.

Therefore option (A) is correct.


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