At the critical temperature, the surface tension of the liquid

Is the same as that at the other temperature

A drop of oil is placed on the surface of the water. Which of the following statement is correct?

It will remain on it as a sphere

It will float at the distorted drop on the water surface

It will partly be as spherical droplets and partly as thin films

pressure inside the drop is greater than outside

pressure inside the drop is lower than outside it

The dimensional formula of surface tension is given by,

M¹L⁰T^-2

Where,

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Surface Tension (T) = Force × Length^-1. . . . . (1)

Since, Force = Mass × Acceleration

And, acceleration = velocity × time^-1= [L T^-2]

∴ The dimensional formula of force = M¹ L¹ T^-2 . . . . (2)

On substituting equation (2) in equation (1) we get,

Surface Tension (T) = Force × Length^-1

Or, T = [M¹ L¹ T^-2] × [L^-1] = M¹T^-2.

Therefore, surface tension is dimensionally represented as M¹T^-2.

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