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Chattisgarh 2020-21 NTSE Stage 1 Answer Key & Question Paper With Solutions

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Chattisgarh 2020-21 NTSE Stage 1 Answer Key & Question Paper With Solutions

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Chhattisgarh 2020-21 NTSE Stage 1 – Question Paper With Solutions

Paper: MAT

Question 1. B, X, D, V, F, T, H


a. I
b. R
c. S
d. Q

Answer: (b)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 1 solution

Question 2. a, Z, f, U, k, P, _ , K, u, F


a. p
b. e
c. x
d. M

Answer: (a)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 2 solution

Question 3. _ bc _ y x d e f w _ u _ h i t s r


a. a z x g
b. a d v g
c. a z v g
d. a d g v

Answer: (c)

abc / zyx / def / wvu / ghi / tsr

Question 4. a b _ _ a b b _ a b _ a


a. b a a b
b. a b a b
c. a b b a
d. a a b b

Answer: (a)

Repeating pattern: abba

Series: abba / abba / abba

Question 5. ACEY, BDFX, CAZF, DBYG, CEGW,____, ECXH


a. DFHY
b. FDWG
c. WGEC
d. DFHV

Answer: (d)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 5 Solution

Question 6. 5, 11, 24, 51, 106, ____


a. 206
b. 207
c. 211
d. 217

Answer: (d)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 6 solution

Question 7. 99, 120, 143, 168, ____


a. 196
b. 197
c. 198
d. 195

Answer: (d)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 7 solution

Question 8. 2, 5, 7, 4, 7, 11, 6, 9, 15, 8, ____, ____


a. 11, 17
b. 10, 19
c. 11, 19
d. 13, 21

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 8 solution

Question 9. 20DE, 3AC, 8BD, __ HI


a. 72
b. 5
c. 24
d. 110

Answer: (a)

D × E = 4 × 5 = 20
A × C = 1 × 3 = 3
B × D = 2 × 4 = 8
H × I = 8 × 9 = 72

Question 10. DF4, HK9, MR25, P__81


a. R
b. Y
c. X
d. L

Answer: (b)

(F – D)2 = 22 = 4
(K – H)2 = 32 = 9
(R – M)2 = 52 = 25
(Y – P)2 = 92 = 81

Direction (Q. No.11 to Q.No.13) :

In the given questions two words/terms are given in the left of :: sign. They have a certain relationship between them. The same relationship exists between the word/term given to the right of :: sign and one of the given alternatives. Choose the correct alternative.

Question 11. Mango : Fruit :: Physics 😕


a. Science
b. Knowledge
c. Machine
d. Book

Answer: (a)

Mango is a type of fruit and thus is a subset of fruit. Similarly, Physics is a science subject and is a subset of Science.

Question 12. R s T : t S r : : P q R : ?


a. P q r
b. P Q r
c. r Q P
d. R q P

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 13 solution

Question 13. Area : Square : : Volume : ?


a. Rectangle
b. Circle
c. Cylinder
d. Square

Answer: (c)

Volume is measured for 3D solids. So here it is cylinder.

Direction (Q.No. 14 to Q.No. 15): In the group of words given below all except one, share a common similarity. Select the odd one:

Question 14.


a. Carrot
b. Radish
c. Garlic
d. Brinjal

Answer: (d)

All except brinjal grow underground.

Question 15.


a. Mumbai
b. Bhopal
c. Karnataka
d. Hyderabad

Answer: (c)

Karnataka is a state while Mumbai, Bhopal and Hyderabad are all capital of states.

Question 16. If in a code language “ R A N D O M “ is coded as “UDQGRP”’, then “CORONA” will be coded as :


a. FRTRQU
b. FRURQD
c. ANDRCO
d. OCORAN

Answer: (b)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 16 solution

Direction (Q.No. 17 to Q.No 18): If in a certain code language :

I. ‘Mango is sweet’ is written as ‘han man run’

II. ‘Boys eat mango’ is written as ‘tak han pat’

III. ‘Girls like sweet’ is written as ‘tuku puku man’

IV. ‘Boys like corn’ is written as ‘puku tak tak’

Then choose the correct alternative in the given question.

//Decoding the code for Q17-18:

Mango – han

Sweet – man

Boys – tak

Girls – tuku

Like – puku

Eat – pat

is – run

Corn cannot be decoded since the code for “Boys like corn” is “puku tak tak”//

Question 17. ‘Mango is corn’ will be written as :


a. Han man tak
b. Han run rak
c. Rak tak han
d. Han man puku

Answer: Bonus

From the codes for mango and is ‘Mango is corn’ may be written as ‘Han run rak’. But since corn is not determined, this cannot be confirmed.

Question 18. ‘ tuku pat rak’ would correctly mean :


a. Girls eat corn
b. Boys eat sweet
c. Mango is corn
d. Girls like corn

Answer: Bonus

From the codes Tuka and pat, ‘ Tuka pat rak ‘ may be ‘ Girls eat corn’. But since rak is not given in the given codes, this cannot be confirmed.

Direction (Q.No.19 to Q.No.20): If in a certain code language it is written:

I. ‘HEICOPTER’ as ‘8539367259’

II. ‘OCTOPINE’ as ‘63267955’

III. ‘NORTHGILA’ as ‘569287931’

IV. ‘VIRTOUS’ as ‘4992631’

Then choose the correct alternative in the given questions.

Decoding from the given words and codes: Code of each letter is the sum of digits of the serial number in the order of letters.

Examples:

A = 1

J = 1 (10 ⇒ 1 + 0 = 1),

K = 2 (11 ⇒ 1 + 1 = 2),

Z = 8 (26 ⇒ 1 + 1 = 2)

Note: This coding logic works for OCTOPINE, NORTHGILA and VIRTOUS but not for HEICOPTER. The code for HEICOPTER has 9 letters but its code has 10 digits. If HEICOPTER is replaced with HELICOPTER, the coding logic works for it as well.

Question 19. ‘GALVAN’ will be written as :


a. 713515
b. 713415
c. 714517
d. 714315

Answer: (b)

From the explained coding logic: G = 7, A = 1, L = 3, V = 4, N = 5

So, GALVAN will be coded as 713415.

Question 20. ‘69575976952’ would correctly mean :


a. FINGERPOINT
b. FNIEGRPOINT
c. NATHOLPOINT
d. NTHULAPOINT

Answer: (a)

From the explained coding logic:

6 = F, 9 = I, 5 = N, 7 = G, 5 = E, 9 = R, 7 = P, 6 = O, 9 = I, 5 = N, 2 = T

So 69575976952 is the code of FINGERPOINT.

Direction (Q.No.21 to Q.No.25):

I. D is the husband of only daughter O of only son M of I.

II. F is the only daughter of her mother L and P is the only grandson of F.

III. Q is the only daughter of the grand daughter-in-law C of the mother-in-law J of wife F of M.

IV. K is the maternal grandfather of N and O.

Then choose the correct alternative in the given questions.

Family tree based on the directions given.

Question 21. What is the relation between P and Q?


a. Brother-Sister
b. Husband-Wife
c. Father-Daughter
d. Grandfather-Granddaughter

Answer: (a)

From the family tree, P and Q are siblings.

Question 22. What is the father-in-law of M?


a. N
b. K
c. P
d. D

Answer: (b)

From the family tree K is the father-in-law of M.

Question 23. Who is O of I ?


a. Son
b. Daughter
c. Grand-daughter
d. Daughter-in-law

Answer: (c)

From the family tree O is the grand-daughter of I.

Question 24. What is the relation between C and N?


a. Brother-Sister
b. Husband-Wife
c. Father-Daughter
d. Grandfather-Granddaughter

Answer: (b)

From the family tree, N and C are husband and wife.

Question 25. What is the relation between K and L?


a. Brother-Sister
b. Husband-Wife
c. Grandfather-Granddaughter
d. Grandfather-grandson

Answer: (b)

From the family tree, K and L are husband and wife.

Direction (From Q.no.26 to Q.No.28):

I. M3 had 4 times caps than that of M5.

II. M1 had 3 times caps than that of M3.

III. M2, M4 and M5 had an equal number of caps.

IV. M1 and M4 had 65 caps together.

Then choose the correct alternative in the given questions.

According to the given statements, the following equations can be inferred.

M3 = 4M5
M1 = 3M3
M2 = M4 = M5
M1 + M4 = 65

Question 26. M2 had how many caps?


a. 13
b. 5
c. 10
d. 20

Answer: (b)

According to the given equations,
M1 + M4 = 65 ⇒ M1 + M2 = 65 …. (1) (Since M2 = M4)
M3 = 4M5 ⇒ M3 = 4M2 (Since M5 = M2)

⇒ (⅓)M1 = 4M2 ⇒ M1 = 12M2 …. (2) (Since M1 = 3M3)

Solving (1) and (2), M2 = 5.

Question 27. What was the ratio of the number of caps of M3 + M4 and M1?


a. 12 : 5
b. 13 : 1
c. 5 : 12
d. 1 : 13

Answer: (c)

M2 = M4 = M5 = 5

M1 + M4 = 65 ⇒ M1 + 5 = 65 ⇒ M1 = 60

M3 = 4M5 = 4 (5) = 20

M3 + M4 = 20 + 5 = 25

So the ratio (M3 + M4) : M1 is 25 : 60 i.e. 5 : 12.

Question 28. How many caps had M3 and M5 together?


a. 25
b. 30
c. 40
d. 65

Answer: (a)

M3 = 20 and M5 = 5

So M3 + M5 = 20 + 5 = 25.

Question 29. Four friends P, Q, R, and S start walking from a point O and after walking 5km, each turn left. If P northwards, Q westwards, R southwards and S eastwards start walking, then after walking how many km, they will meet each other at the same point ?


a. 20 km each
b. 15 km each
c. 35 km each
d. 45 km each

Answer: (a)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 29 Solution

Question 30. In a competition, Rohan obtained more marks than Pinki and Sumit. Gaurav obtained less marks than Pinki but more than Rupa. Sumit obtained more marks than Gaurav but less than Pinki. Then keeping marks obtained in ascending order, who was at the third position?


a. Rupa
b. Sumit
c. Gaurav
d. Rohan

Answer: (b)

The ascending order is as follows:
Rupa < Gaurav < Sumit < Pinki < Rohan

Direction (From Q.No 31 to Q.No.33)

If :

i. Q is in the west of T.

ii. R is in the north-east of Q.

iii. T is in the east of P.

iv. P Is in the south of R.

v. P is in the south-west of S

vi. R and S are in the east of U.

Then choose the correct alternative in the given questions.

The probable positions of U, R, S, Q, P and T are given as follows:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 30 solution

Question 31. Who is in the west of T but in the east of Q ?


a. P
b. U
c. R
d. S

Answer: (a)

P is in the west of T but in the east of Q.

Question 32. Who is in the north of T but in the east of R ?


a. P
b. Q
c. U
d. S

Answer: (d)

S is in the north of T but in the east of R.

Question 33. Who is in the north of Q?


a. P
b. U
c. R
d. S

Answer: (b)

U is in the north of Q.

Question 34. Some boys play either Cricket or Football or Kabaddi or Volleyball. Those who play Cricket do not play Volleyball, those who play Football do not play Kabaddi and those who play volleyball do not play Cricket and Kabaddi both. Which of the following logical venn-diagrams correctly illustrate this situation?

Chhattisgarh NTSE 2021 Stage 1 MAT Question 34


Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 34 solution

Question 35. Which of the Venn-diagrams denotes correct connection between given classes?

India, Shimla, Chief Minister

Chhattisgarh NTSE 2021 Stage 1 MAT Question 35


Answer: (d)

Each state in India has a Chief Minister. One of the Chief Ministers operates from Shimla since it is the capital city of the Indian State of Himachal Pradesh.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 35 solution

Question 36. Most of the students at school have mobile. There is no internet facility in the mobile of some students. Some students use WhatsApp but not email while some students use e-mail but not WhatsApp. Which of the following logical Venn-diagrams correctly illustrate this situation?

Chhattisgarh NTSE 2021 Stage 1 MAT Question 36


Answer: (a)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 36 solutions

In the image: S ⇒ Students; M ⇒ Students having mobile phones; I ⇒ Students having mobiles with the internet; W ⇒ Students using WhatsApp; E ⇒ Students using email.

Direction (From Q.no.37 to Q.No.38): Population of a ward of a city is 600 in which the number of patients of Covid (Cov), Cancer (Canc), Diabetes (Diab), Kidney (Kidn) and of other diseases (Oth) are shown by the following Venn-diagram:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 37 - 38

Question 37. People of which disease has the maximum danger of Covid?


a. Kidney
b. Cancer
c. Diabetes
d. Other diseases

Answer: (b)

Intersection of Cancer and Covid is 60 + 10, i.e 70. Maximum intersecting disease with Covid is Cancer.

Question 38. How many people have no disease?


a. 220
b. 280
c. 320
d. 55

Answer: (c)

Total number of people of the ward = 600

Total number of people with disease = 50 + 45 + 60 + 10 + 5 + 5 + 5 + 30 + 70 = 280

Number of people without any disease = 600 – 280 = 320

Question 39. If m = n (mod5) iff 5 divides (m – n), e.g. 7 = 2 (mod 5), 8 = 3 (mod5), then 27 = ? (mod 8).


a. 2
b. 3
c. 4
d. 7

Answer: (b)

It is given, m = n(mod5) means (m – n) is divisible by 5.

So, 27 = a(mod 8) means (27 – a) is divisible by 8.

Positive integers less than 27 that are divisible by 8 are 24, 16, 8.

24 = (27 – 3); So, from the given options a = 3.

Question 40. When 5 divides 8 gives remainder 3, 7 divides – 4 gives remainder 3, 2 divides -1 gives remainder 1, then when 4 divides – 6 gives remainder?


a. 2
b. 0
c. 3
d. 1

Answer: (a)

Dividend = Divisor(Quotient) + Remainder. Reminder is a positive integer.

(-6+4+4)=2

Question 41. If the given interchanged are made, which one of the equations given in the options would be correct?

(i) signs + and x

(ii) numbers 4 and 5


a. 5 × 4 + 20 = 40
b. 5 × 4 + 20 = 85
c. 5 × 4 + 20 = 104
d. 5× 4 + 20 = 95

Answer: (c)

On interchanging signs + and ×, and numbers 4 and 5, we get,
4 + 5 × 20 = 104

Question 42. Digit at unit place of (-1+1+1-1+1+1-1+1+1)73 is:


a. 3
b. 9
c. 7
d. 1

Answer: (a)

(-1+1+1-1+1+1-1+1+1)3 = (3)73

The unit digit of (3)73 is 3.

Direction (From Q.No.43 to Q.No.45): P, Q, R, S, T and U are six members in a house. P goes to the city every third day and returns in the evening at 6 O’clock on the fifth day but P is not the eldest. T, who is not the youngest, goes to the city on the first day and returns on the fourth day. S who is younger than P but elder than U and Q remains out of the house every day from 8 am to 8 pm. R who is younger than T but elder than P does not stay at home on the second and fifth day. No one is younger than Q. Every member stays at home on Sunday.

P

   

Out

Out

Out till 6 PM

   

Q

             

R

 

Out

   

Out

   

S

Out from

8 AM to 8 PM

Out from

8 AM to 8 PM

Out from

8 AM to 8 PM

Out from

8 AM to 8 PM

Out from

8 AM to 8 PM

Out from

8 AM to 8 PM

 

T

Out

Out

Out

Out

     

U

             

If T > R > P > S > U > Q.

Question 43. Who is the fourth younger member in the house?


a. R
b. P
c. S
d. U

Answer: (b)

From the given instructions: The order of the six members from eldest to youngest is T > R > P > S > U > Q.

So the fourth youngest member is P.

Question 44. If the first day is assumed to be Monday, then at the time of dinner on the fifth day at 7 O’clock evening, how many members will present in the house?


a. 5
b. 4
c. 6
d. 3

Answer: (b)

From the table, 4 members (P, Q, T and U) will be present at home on 5th day 7 PM.

Question 45. Who is the eldest member in the house


a. Q
b. U
c. T
d. S

Answer: (c)

From the given instructions: The order of the six members from eldest to youngest is T > R > P > S > U > Q. So the eldest member is T.

Question 46. A herd of monkeys gathered in the morning at 8 O’clock. After that every 2 hours 5 monkeys went out and 10 monkeys came in. At 4 O’clock afternoon, the number of monkeys became 50. How many monkeys were in the herd at 9 O’clock in the morning?


a. 20
b. 25
c. 40
d. 30

Answer: (d)

Number of monkeys at 4 PM = 50

Number of hours between 8 AM and 4 PM = 8 hours

Let the number of monkeys at 8 AM be a.

a + (10 – 5) x 4 = 50 (Since every 2 hours 5 monkeys left and 10 monkeys arrived.)

a + 5 x 4 = 50

a + 20 = 50

a = 30

Question 47. Arrange the following in a meaningful sequence:

1. Paneer 2. Palak – Paneer 3. Milk 4. Buffalo 5. Grass


a. 4, 5, 1, 3, 2
b. 5, 4, 1, 2, 3
c. 3, 5, 4, 1, 2
d. 5, 4, 3, 1, 2

Answer: (d)

Buffalo eats grass and gives milk. Milk is used to make paneer. Using paneer, the dish palak-paneer is cooked.

Question 48. Arrange the following in a meaningful sequence:

1.District, 2.Village 3. State 4. Town.


a. 2, 1, 4, 3
b. 2, 3, 4, 1
c. 2, 4, 1, 3
d. 3, 2, 1, 4

Answer: (c)

Village is usually smaller than a town and a group of towns make a district. Districts are administrative divisions of a state.

Question 49. Salary of P is 50% more than Q but 50% less than R. If salary of Q is Rs. 15,000, then what is the salary of R?


a. Rs. 45,000
b. Rs. 15,000
c. Rs. 22,500
d. Rs. 27,000

Answer: (a)

Salary of P = 50% more than Q

Salary of P = 50/100 Q + Q

= 1.5(15000)
= Rs. 22500

Salary of R – 50% R = Salary of P

R – 0.5R = Rs. 22500
0.5R = Rs. 22500

= Rs. 45,000

Question 50. If ages of Mohan, Sohan and Rohan are in the ratio 2 : 3 : 4, ages of Sohan, Rohan and Tori are in the ratio 3 : 4 : 3 and if the present age of Mohan is 12 years, then how many years is the age of Tori?


a. 27
b. 24
c. 18
d. 16

Answer: (c)

The ratio of ages of Mohan, Sohan, Rohan and Tori is 2:3:4:3.

Let the ages of Mohan, Sohan, Rohan and Tori be 2a, 3a, 4a and 3a respectively.

Given: Age of Mohan is 12 years. So 2a = 12 years ; a = 6

Age of Tori = 3a = 18 years.

Question 51. If for 30 animals 210 kg. grains are sufficient for 18 days, then for 24 animals 280 kg. grains are sufficient for how many days?


a. 28
b. 30
c. 35
d. 23 ¼

Answer: (b)

210 kg grain for 30 animals is sufficient for 18 days.

So Food grain required for 1 animal for 1 day = 210 / 30 × 18 = 7/18 kg

Food grain required for 24 animals for 1 day = ⅞ × 24 = 28/3 kg

Given that, 280 kg grains are available:

Number of days it will feed 24 animals =

\(\begin{array}{l}\frac{280}{\frac{28}{3}}\end{array} \)

= 30 days

Question 52. Half of one-fourth of one-third of a number is 8. Then what will be ⅜ of that number?


a. 35
b. 35
c. 70
d. 72

Answer: (d)

Let the number be a.

\(\begin{array}{l}\frac{1}{2}\left ( \frac{1}{4}(\frac{1}{3})(a) \right ) = 8\end{array} \)
\(\begin{array}{l}\frac{a}{24} = 8\end{array} \)

a = 8 × 24

⅜ (8 × 24) = 72

Question 53. A number is reduced by 18 if it is divided by 7. That number is:


a. 3
b. 24
c. 21
d. 0

Answer: (c)

Let the number be a.

a/7 = a – 18

6a = 7 × 18

a = 21

Direction (Q. No.54 to Q. No. 58): Choose the missing number (?) from the given alternatives.

Question 54. Choose the missing number (?)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 54


a. 89
b. 88
c. 223
d. 98

Answer: (a)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 54 solution

Question 55. Choose the missing number (?)

1

2

3

11

7

5

120

45

?


a. 18
b. 17
c. 16
d. 15

Answer: (c)

112 – 12 = 121 – 1 = 120

72 – 22 = 49 – 4 = 45

52 – 32 = 25 – 9 = 16

Question 56. Choose the missing number (?)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 56


a. 240
b. 280
c. 96
d. 84

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 56 solution

Question 57. Choose the missing number (?)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 57


a. T
b. S
c. U
d. Y

Answer: (d)

8 + 11 = 19. 19th letter of the English alphabet is S.

4 + 12 = 16. 16th letter of the English alphabet is P.

6 + 10 = 16. 16th letter of the English alphabet is P.

14 + 11 = 25. 25th letter of the English alphabet is Y.

Question 58. Choose the missing number (?)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 58


a. 64
b. 80
c. 100
d. 54

Answer: (b)

From the first two given images:

(25 – 15)2 + (17 – 12)2 = 100 + 25 = 125

(13 – 8)2 + (14 – 6)2 = 25 + 64 = 89

Similarly, (17 – 9)2 + (16 – 12)2 = 64 + 16 = 80

Direction (From Q. No. 59 to Q. No. 60): In each of the following questions an Assertion (A) followed by a Reason (R) is given.

Choose the correct alternative from the following:

I. If both (A) and (R)are true and (R) is the correct explanation of (A)

II. Both (A) and (R) are true but (R) is not the correct explanation of (A)

III. (A) is true but (R) is false.

IV. (A) is false but (R) is true.

Question 59. Assertion (A) : covid-19 is a pandemic

Reason (R) : Covid-19 is an epidemic spread from foregin.


a. IV
b. III
c. II
d. I

Answer: (c)

Pandemic means a disease that spreads over a whole country or the whole world. Epidemic means a disease that spreads to a large number of people in a region.

So both A and R are true. But R is not the reason for the stated assertion.

Question 60. Assertion (A) : A person of any age can become a scientist.

Reason (R) : Necessary study for becoming a scientist is not completed in less than 50 years.


a. I
b. II
c. III
d. IV

Answer: (c)

A is true. There is no specific time period related to scientific studies and so R is not true.

Direction (Q. No. 61 to Q. No. 62): In each of the following questions one statement and two arguments (I) and (II) are given. Choose the correct alternative from the following :

A. Only argument (I) is strong.

B. Only argument (II) is strong.

C. Neither argument (I) nor argument (II) is strong.

D. Both the arguments (I) and (II) are strong.

Question 61. Statements: Should there be big ponds in each city?

Arguments : (I) Yes, to maintain the water level of cities it is necessary.

(II) No, there is the fear of drowning of small children.


Answer: (a)

There should be big ponds to maintain the water level in cities. The only argument I is strong.

Question 62. Statements: Should shops selling foreign goods be closed?

Arguments : (I) Yes, domestic industries will develop from it.

(II) No, the export of domestic goods will get affected.


Answer: (d)

Closing the selling of foreign goods will be helpful for domestic industries but it will affect the exports since foreign relations will be affected.

Direction (From Q. No. 63 to Q. No. 64) : In each of the following questions, a statement and two conclusions (I) and (II) are given. Choose the correct alternative from the following:

A. Only conclusion (I) follows

B. Only conclusion (II) follows

C. Both the conclusion (I) and (II) follow.

D. Neither conclusion (I) nor conclusion (II) follows.

Question 63. Statements: 200 parks constructed in a city. From these, sports material for children is kept in 160 parks.

Conclusion:

(I) In 20% parks sports materials are kept for adults.

(II) 80% of children go to the park.


Answer: (d)

The given statement neither provides any information on sports material for adults nor on the percentage of children going to parks. Both conclusions do not follow.

Question 64. Statements: Suggestions of young educationists are included in the education system.

Conclusion:

(I) At present there is a demand of young thought.

(II) Suggestions given by young educationists were good.


Answer: (b)

From the given statement it can be concluded that suggestions given by young educationists are good. The statement does not express anything on the demand of young thought. Only conclusion (II) follows.

Direction (From Q. No. 65 to 66): In each of the following questions two statements (I) and (II) are given. There may be the cause and effect relationship between the two statements Read both the statements and mark your answer as:

A. If statement (I) is the cause and statement (II) is its effect.

B. If statement (II) is the cause and statement (I) is its effect.

C. If both the statement (I) and (II) are independent causes.

D. If both the statement (I) and (II) are effects of independent causes.

Question 65. Statement: (I) Parents prohibit their boys from playing cricket.

(II) Boys play cricket all day.


Answer: (b)

Parents prohibiting their boys from playing cricket is a possible effect of the happening that the boys play cricket all day.

Question 66. Statement: (I) Canals constructed in each village.

(II) Each canal was connected from big dams.


Answer: (d)

There are different types of canals serving different purposes. In villages, canals are constructed to transport water from other water bodies like rivers. Canals from big dams are built to transport water to different cities and villages. Both statements are the effects of different causes.

Direction (From Q. No. 67 to 71): In each of the following questions one question and two statements (I) and (II) are given. You have to decide whether the data provided in the statement are sufficient to answer the questions. Read both the statements and choose the correct alternative from the following :

A. (I) alone is sufficient.

B. (II) alone is sufficient.

C. Both (I) and (II) together are sufficient but not alone.

D. (I) and (II) together are also insufficient.

Question 67. In which subject Sumit scored maximum marks ?

Statement I: Sumit appeared in Maths, Physics, Biology and Social Science.

Statement II: Sumit scored marks in Biology as that obtained in Physics and Social Science minus Maths.


Answer: (d)

Physics/ Social science > Biology and Physics/ Social science > Maths

Between Physics and Social science which one is higher cannot be concluded.

Insufficient information.

Question 68. What is the age difference between Bambam and Chhotu?

Statement I: Chhotu is 20 years younger than Munmun.

Statement II: Bambam is 5 year older than Munmun.


Answer: (c)

Both the statements are required to arrive at the age difference between Bambam and Chottu.

Question 69. How is ‘MANGO’ written in the code language?

Statement I: In a certain code, ‘TEMPO’ is coded as ‘ETLMN’.

Statement II: In a certain code ‘RACKET’ is coded as ‘TEKCAR’.


Answer: (b)

The statement (I) cannot be decoded based on any logic. But the word MANGO can be coded based on the logic in Statement II.

Question 70. Which number is the largest?

Statements I: Q is not smallest but R is larger than P and S.

Statement II: S is smaller than Q but larger than T.


Answer: (d)

From the given statements: R > P and S; Q > S >T

Even by combining information from both the statements, it cannot be concluded between Q and R, which is the largest.

Question 71. Who won the race?

Statement I: Sita followed by Rita and Gita were top three runners.

Statement II: Mohan, Sohan and Raina were top three runners.


Answer: (a)

Only in statement (I) one runner is ranked above the other 2 runners.

Information in Statement (II) is not sufficient to determine the winner.

Direction (From Q. No. 72 to 73): In each of the following questions a statement followed by two courses of action (I) and (II) are given. You have to assume everything in the statement is true, then decide which of the suggested courses of action logically follows.

A. If only (I) follows

B. If only (II) follows

C. If either (I) or (II) follows

D. If neither (I) nor (II) follows

Question 72. Statement: A pandemic spreading from the contact of each other is to knock the city.

Courses of action:

I. Going out of the house should be restricted.

II. Bearing masks and keeping a necessary distance from each other must be kept in mind before going out.


Answer: (c)

Restricting travel, wearing masks and social distance are measures to tackle a pandemic spreading. Both courses of action (I) and (II) follow.

Question 73. Statement: During journey, mobile gets switched off.

Courses of action:

I. We should travel with a charger.

II. We should try to keep the switch on.


Answer: (d)

The courses of actions given here are precautionary suggestions. They don’t follow the event of a mobile getting switched off.

Direction (From Q. No. 74 to 75): In each of the following questions one statement and two assumptions (I) and (II) are given. Decide which of the assumptions is implicit in the statement.

Give answer:

A. If only assumption (I) is implicit.

B. If only assumption (II) is implicit.

C. If either (I) or (II) is implicit.

D. If neither (I) nor (II) is implicit.

Question 74. Statement: Teaching based on surgery of frogs is stopped.

Assumptions:

I. Teaching of this surgery has no benefit.

II. It is necessary for the conservation of the environment.


Answer: (b)

Only the assumption on the conservation of the environment is implicit.

Question 75. Statement: In view of the terrorist attack, the operation of trains has been stopped.

Assumptions:

I. Terrorists can derail trains.

II. Driving team of the train is scared.


Answer: (a)

Only the assumption regarding terrorists derailing the train is implicit.

Question 76. How many triangles are there in the given figure, in which at least one square is completely inside?

Chhattisgarh NTSE 2021 Stage 1 MAT Question 76


a. 10
b. 12
c. 16
d. None of these

Answer: (b)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 76

Question 77. What is the number of vertices in the given figure, where four or more line segments meet

Chhattisgarh NTSE 2021 Stage 1 MAT Question 77


a. 11
b. 15
c. 17
d. None of these

Answer: (a)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 77 solution

Question 78. What is the minimum number of parallel lines required to make the given figure

Chhattisgarh NTSE 2021 Stage 1 MAT Question 78


a. 4
b. 10
c. 18
d. None of these

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 78 solution

Question 79. How many entry gates are there in the given figure?

Chhattisgarh NTSE 2021 Stage 1 MAT Question 79


a. 5
b. 7
c. 8
d. 10

Answer: (b)

It can be seen that there are 3 entry gates on the left lines and 4 on the top lines. In total there are 7 entry gates .

Question 80. What is the minimum number of straight lines required to make the given figure?

Chhattisgarh NTSE 2021 Stage 1 MAT Question 80


a. 20
b. 22
c. 18
d. None of these

Answer: (c)

Hexagon sides + Pentagon sides + Quadrilateral sides + 3 odd lines.

Total number of lines = 6 + 5 + 4 + 3 = 18

Direction (From Q. No. 81 to 83): In each of the following questions a sheet of paper (P) and four boxes are given. Select the box that is similar to a box formed by folding the paper (P).

Question 81. Select the box that is similar to a box formed by folding the paper (P).

Chhattisgarh NTSE 2021 Stage 1 MAT Question 81

Chhattisgarh NTSE 2021 Stage 1 MAT Question 81


a. (1), (3) and (4) only
b. (1) and (2) only
c. (2) and (4) only
d. (3) only

Answer: (a)

(1) (3) and (4) can be obtained by folding the given paper (P). (2) cannot be obtained since if the sides with 2 and 1 are as shown, 5 will be at the bottom.

Question 82. Select the box that is similar to a box formed by folding the paper (P).

Chhattisgarh NTSE 2021 Stage 1 MAT Question 82

Chhattisgarh NTSE 2021 Stage 1 MAT Question 82


a. (1) and (2) only
b. (2) and (3) only
c. (1) and (4) only
d. (1), (2), (3) and (4) all

Answer: (b)

Only (2) and (3) can be obtained by folding the given paper (P).

Question 83. Select the box that is similar to a box formed by folding the paper (P).

Chhattisgarh NTSE 2021 Stage 1 MAT Question 83

Chhattisgarh NTSE 2021 Stage 1 MAT Question 83


a. (1), (3) and (4) only
b. (1) and (2) only
c. (2), (3) and (4) only
d. (4) only

Answer: Bonus

– Only (1) and (3) can be obtained by folding the given paper (P).

– (2) cannot be obtained since if the sides with 1 and 5 are as shown, 4 will be at the bottom.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 83

– By comparing (4) to the alternate net of the given cube shown above, it can be seen that the orientation of the 6 dots in (4) is wrongly represented.

Question 84. Four positions of a dice are shown below. How many dots are contained on the face opposite to that containing four dots?

Chhattisgarh NTSE 2021 Stage 1 MAT Question 84


a. 4
b. 1
c. 2
d. 3

Answer: (b)

i. From figure 3 and 4: Dots 5, 3 and 2 are adjacent to the 4 dots side.
ii. From figure 1 and 2: Dots 5, 3 and 2 are adjacent to 1 dot side.

Thus, it can be observed that only dot 1 is on the opposite face to dot 4.

Question 85. A cube painted red on all of its faces is cut into 64 small cubes of equal size. How many small cubes are painted red on at least two faces ?


a. 4
b. 8
c. 32
d. 24

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 85

No. of cubes which will be painted red on three sides = 8
No. of cubes which will be painted red on two sides = 24

Total no. of cubes with at least two sides painted red = 24 + 8 = 32

Direction (From Q. No. 86 to 88): Choose the correct alternative from the answer figures in place of question mark (?), which will continue the series.

Question 86. Choose the correct alternative from the answer figures.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 86

Answer figures:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 86


Answer: (d)

1 and 3 have sharp star-like arms. 2 and 4 will have only gear teeth-like arms.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 86 solution

Question 87. Choose the correct alternative from the answer figures.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 87 solution

Answer figures:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 87


Answer: (c)

i. The position of the rectangle and sign ‘x’ is being interchanged in each step.
ii. Triangle, sign ‘=’ and sign ‘+’ are changing their position in a series.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 87 solution

Question 88. Choose the correct alternative from the answer figures.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 88

Answer figures:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 87


Answer: (b)

– In the middle row, the first two symbols are interchanged in the consequent figures in the given series. The options that follow this pattern are a and b.

– In the series, the -ve sign is accompanied by left bracket and +ve sign is accompanied by right bracket. so option a is eliminated.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 87 solution

Direction (From Q. No. 89 to 90): In the following question, figues (1) and (2) are related in a particular manner. Establish the same relationship between figues (3) and (4) by choosing a figure from amongst the alternatives, which would replace question mark in figure (4).

Question 89. Choose the correct figure from amongst the alternatives.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 89

Answer figures:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 89


Answer: (a)

The triangles in 1 and 2 are in the same orientation. 1 has three triangles while 2 has two triangles. The number of circles in 1 and 2 remains the same.

By applying the same logic to 3 and 4, among the given options, (a) is the answer.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 89 solution

Question 90. Choose the correct figure from amongst the alternatives.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 90

Answer figures:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 90


Answer: (c) or (d)

i. The inner shape and outer shape get interchanged.

ii. The number of dots increases.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 90 solution

The orientation of the triangle in 4 can be any way, since circles in 1 and 2 cannot exhibit orientation change, even option (d) is a possible answer.

Direction (From Q. No. 91 to 92): In the following questions, out of the four figures marked as (A), (B), (C) and (D), three are similar in a certain manner, but one is different from the other. Choose the figure which is different from others.

Question 91. Choose the figure which is different from others.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 91 solution


Answer: (d)

Only in option d, the scale divisions are inside the rectangle.

Question 92. Choose the figure which is different from others.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 92


Answer: (b)

Only in option b, the ellipse is shaded.

Direction (From Q. No. 93 to 94): In the following questions, out of the four figures marked as (A), (B), (C) and (D), three are similar in a certain manner, but one is different from the other. Choose the figure which is different from others.

Question 93. B60X3ER

Chhattisgarh NTSE 2021 Stage 1 MAT Question 93


Answer: (a)

A is the mirror image of B60X3ER.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 93 solution

Question 94. CORP457SN

Chhattisgarh NTSE 2021 Stage 1 MAT Question 95


Answer: (b)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 94 solution

Direction (From Q. No. 95 to 96): In the following questions Choose the alternative which most closely resembles the water image of the given combination.

Question 95. PATERN675

Chhattisgarh NTSE 2021 Stage 1 MAT Question 95


Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 95 solution

Question 96. VULTURE4329

Chhattisgarh NTSE 2021 Stage 1 MAT Question 96


Answer: (a)

Chhattisgarh NTSE 2021 Stage 1 MAT Question 96 solution

Direction (From Q. No. 97 to 98): Select a suitable figure from the four alternatives that would complete the figure matrix.

Question 97. Select a suitable figure from the four alternatives.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 97

Chhattisgarh NTSE 2021 Stage 1 MAT Question 97


Answer: (b)

The figures in the second column have an open side compared to the first column. The closing lines/curves on the opposite sides of the open side are removed in the third column. Also, the figure is made symmetric by adding small curves.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 97 solution

Question 98. Select a suitable figure from the four alternatives.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 98

Chhattisgarh NTSE 2021 Stage 1 MAT Question 98


Answer: (d)

A curved line added to the image on top of the previous column and the small circles are moved to the bottom.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 98 solution

Direction (From Q. No. 99 to 100): Select a figure in place of (?) from amongst the given alternatives, which would complete the pattern of the question figure.

Question 99. Question figure:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 99

Chhattisgarh NTSE 2021 Stage 1 MAT Question 99


Answer: (c)

There should be 3 lines in the inner circle, 3 (+) signs and 3 small circles in the missing image.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 99 solution

Question 100. Question figure:

Chhattisgarh NTSE 2021 Stage 1 MAT Question 100

Chhattisgarh NTSE 2021 Stage 1 MAT Question 100


Answer: (a)

There should be one dot in the inner circle in the missing portion. The small circle on the arrow should be positioned as in the arrow on the diagonally opposite vertex.

Chhattisgarh NTSE 2021 Stage 1 MAT Question 100 solution

Chhattisgarh NTSE 2020 Stage 1 SAT Paper

Paper: SAT

Physics

Question 1. Speed of bus is increased from 36 km/hour to 72 km/hour in 10 second its acceleration is:


a. 3.6 meter/second2
b. 5 meter/second2
c. 2 meter/second2
d. 1 meter/second2

Answer: (d)

Given:initial velocity, u = 36km/hr

final velocity v= 72 km/hr

u = 36 km/hr = 36 × 5/18 = 10 m/s; v = 72 km/hr = 72 × 5/18 = 20 m/s

Acceleration = (final velocity – initial velocity) / time = (20-10)/10 = 10 / 10 = 1 m/s²

Question 2. Two particles are placed at some distance from each other. Keeping the distance between them unchanged the mass of each particle is doubled then the value of gravitational force between them will be:


a. ¼ times
b. 4 times
c. ½ times
d. 2 times

Answer: (b)

Gravitational force, F = GMm/r²

The new force after both masses are doubled is

F = G(2M)(2m) / r² = 4Gmm / r² = 4 times older force

Question 3. The momentum of a bullet of mass 20 gram fired from a gun is 10 kg. meter/second. The kinetic energy of this bullet is:


a. 5 kilojoule
b. 1.5 kilojoule
c. 2.5 kilojoule
d. 25 kilojoules

Answer: (c)

Given: mass = 20 g = 20×10⁻³ kg; momentum, p = 10kg.m/s

K.E. =p² / 2m = 10 × 10 / 2 × 0.02

K.E. = 2500 J = 2.5 kJ

Question 4. An investigator team transmitted an ultrasound signal to the sea bed. The signal is received back in 4 seconds. If the speed of sound in seawater is 1500 meter/second then the depth of the sea is:


a. 3 km
b. 6 km
c. 4.5 km
d. 1.5 km

Answer: (a)

Distance = speed x time

2 x distance = 1500 x 4 = 6000m

Distance = 6000 / 2 = 3000 m = 3 km

Question 5. A conducting wire of resistance 4 R Ω is bent in the form of a circle what is the effective resistance between the ends of the diameter:


a. R Ω
b. 4 R Ω
c. 1/R Ω
d. 1/4R Ω

Answer: (a)

When a conducting wire is bent in the form of a circle, the upper and lower semicircles have a resistance of 2R each. While calculating the effective resistance between the ends of the diameter, upper and lower semicircles will be in parallel.

1/Rₛ = 12/R + 12/R = 22/R = 1/R

Effective resistance, Rₛ = R

Question 6. The time period of 500Hz wave will be:


a. 0.002 second
b. 0.02 second
c. 0.2 second
d. 2 second

Answer: (a)

Given = frequency, f = 500 Hz

f =1 / T, where T is the time period.

T = 1 / 500 = 0.002 s

Question 7. The force exerted on a conductor placed in a uniform magnetic field is maximum when the angle between the magnetic field and conductor is:


a. 45o
b. 90o
c. 30o
d. 60o

Answer: (b)

F = BILsinθ, θ being the angle between magnetic field and conductor.

F is maximum when θ is maximum. Sinθ is maximum when θ is 90o.

Question 8. The refractive indices of four substances, A, B, C and D are respectively 1.50, 1.36, 1.70 and 1.31. Out of these substances which substance will have a maximum speed of light:


a. A
b. B
c. C
d. D

Answer: (d)

Refractive index is inversely proportional to the speed of light. The substance with the least refractive index will have the maximum speed for light passing through.

Question 9. A convex lens of focal length 8cm. Forms a real image of the same size as the object. Then the distance between object and image will be:


a. 8 cm
b. 16 cm
c. 32 cm
d. 24 cm

Answer: (c)

A convex lens forms an image of the same size of the object when the object is at 2F, and the image is formed at 2F as well. Thus the distance between object and image is 2F + 2F = 4F = 4×8 = 32 cm.

Question 10. According to Oersted’s experiment of the magnetic effect of electric current if wire kept parallel and above the magnetic needle and current is flowing from south to north direction then deflection of the north side of the magnetic needle is towards:


a. North
b. South
c. East
d. West

Answer: (d)

According to the right-hand thumb rule, if the thumb points towards the direction of the current, the curled fingers point towards the direction of the magnetic field. If the current is from south to north, the magnetic field will be from the east towards west.

Question 11. The main constituents of petroleum gas is:


a. Butane
b. Propane
c. Ethane
d. Methane

Answer: (a)

Liquified petroleum gas mainly consists of propane and butane with butane being the major constituent.

Question 12. The ratio of displacement to the distance of a moving object it:


a. More than 1
b. Less than 1
c. Equal to or less than 1
d. Equal to or more than 1.

Answer: (c)

The ratio of displacement to the distance of a moving object is equal to or less than 1. The distance travelled by any body cannot be equal zero while the displacement of a body can be zero and it can also be less than that of the distance travelled by the body.

Thus, Displacement / Distance ≤ 1

Question 13. Which of the following have more effect of burning?


a. Hot air
b. Water vapour
c. Hot water
d. Boiled water

Answer: (b)

Hot air and Hot water could be of any temperature below 100°C, boiled water has a temperature of 100°C, and water vapour is definitely of a temperature higher than 100°C.

The latent heat of vaporization, which is the energy required to change water to vapour is only present in Water vapour, thus it has more energy and it will cause more burning effect.

CHEMISTRY

Question 14. 30 g Sugar dissolves in 410 g of solvent water in a solution. The percentage concentration of the solution will be:


a. 68%
b. 6.81%
c. 0.68%
d. 7.31%

Answer: (b)

The mass percentage of a solution is given by:

Mass per cent =[ Mass of solute ∕ (Mass of solution)] ✕ 100 %

Thus, mass percent of the solution = [ 30 g / 440 g] ✕ 100 % = 6.81%

Question 15. In molecular formula CH3 – CH = CH2 the number of single bonds are:


a. 9
b. 8
c. 7
d. 6

Answer: (c)

The total number of single bonds in propene (CH3 – CH = CH2) is 7.

Chhattisgarh NTSE 2021 Stage 1 SAT Question 15 solution

Question 16. Acid in which both functional groups – OH and – COOH present is:


a. Tartaric acid
b. Ethanoic acid
c. Formic acid
d. Oxalic acid

Answer: (a)

The acid in which both functional groups – OH and – COOH present is Tartaric acid.

Chhattisgarh NTSE 2021 Stage 1 SAT Question 16 solution

Question 17. Ionization energy increases from left to right across a period because:


a. Less energy is required to release electrons from the outer shell.
b. Nuclear attraction decreases on electrons
c. Nuclear attraction increases on electrons
d. Atomic size increases gradually.

Answer: (c)

Ionisation energy increases from left to right across a period because the nuclear attraction increases on electrons. As we proceed from left to right in a period, the atomic number increases.

Thus, there is a significant increment in the nuclear charge and also the electrons across a period are present in the same shell. The valence electrons thus are held strongly by the higher effective nuclear charge. Thus, Ionization energy increases from left to right across a period.

Question 18. Element X loses one electron, element Y gains one electron and forms the compound XY. Which of the following is the property of the compound:


a. Soluble in water
b. Possess low melting point
c. Is a liquid
d. Bad conductor of electricity

Answer: (a)

The type of compound formed by the losing and gaining of electrons are called Ionic compounds.

Ionic compounds have a high melting point due to the presence of strong electrostatic forces of attraction between the constituents of the compound. They are solids at room temperature and are good conductors of electricity in the molten state or in an aqueous solution.

The polar water molecules have a strong affinity for charged ions and the charged ions become solvated as they dissociate in the water. Thus, ionic compounds are soluble in water.

Question 19. Which of the following elements would lose an electron easily?


a. Na
b. CI
c. F
d. O

Answer: (a)

The elements present to the extreme left side of the periodic table tend to lose electrons easily as losing an electron will give them a stable octet configuration. Thus, sodium will lose an electron easily.

Question 20. What would be the electronic configuration of a positively charged magnesium ion (Mg2+)?


a. 2, 8, 2
b. 2, 8
c. 2, 8, 4
d. 2, 8, 8

Answer: (b)

The atomic number of Magnesium is 12. The electronic configuration of magnesium in its neutral state is 2, 8, 2. When Mg → Mg+2, the 2 outermost electrons leave and the electronic configuration becomes (2, 8).

Question 21. Which one of the following metals does not corrode easily?


a. Iron
b. Copper
c. Magnesium
d. Platinum

Answer: (d)

Metals corrode naturally when they react with air, moisture, and saltwater. Iron. copper and magnesium react with the mentioned factors and produce their respective oxides, causing corrosion. Platinum which is the least reactive metal of all forms a protective film of oxide which isolates the metal from the environment, thus reducing the rate of corrosion.

Question 22. The number of molecules present in 8.0 g of oxygen molecule will be:


a. 2.011 × 1023
b. 3.011 × 1023
c. 1.505 × 1023
d. 6.022 × 1023

Answer: (c)

In 32 gram of oxygen = 6.022 × 1023 number of oxygen molecules are present.

⇒ 1 gram of oxygen = 6.022 × 1023 / 32 number of oxygen molecules

⇒ 8 gram of oxygen = [ (6.022 × 1023 / 32 ) ✕ 8] number of oxygen molecules

= 1.505 × 1023 number of molecules

Question 23. Which of the following hydrocarbon contains a triple bond?


a. C3H4
b. C2H6
c. C3H6
d. C3H8

Answer: (a)

The hydrocarbon consisting of a triple bond is propyne( C3H4).

Chhattisgarh NTSE 2021 Stage 1 SAT Question 23 solution

Question 24. In blast furnace, Fe2O3 is reduced to Fe by:


a. C
b. CO
c. SiO2
d. CaCO3

Answer: (b)

The reduction of Fe2O3 to Fe in a blast furnace is done by carbon monoxide (CO).

Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)

Question 25. The atomic number of four elements P, Q, R, and S are 6, 10, 12, and 17 respectively. Which two elements can combine to form a covalent compound:


a. P and R
b. Q and S
c. P and S
d. R and S

Answer: (c)

A covalent compound is formed by the sharing of electrons between the constituents of the compound. Element P, Q, R and S with atomic number 6, 10, 12 and 17 are carbon, Neon, Magnesium and chlorine respectively.

Covalent bonds are usually formed between non -metals. Thus, element P and S will share electrons amongst themselves to form a covalent compound.

Question 26. The formula of aluminium nitride is AIN, then the formula of magnesium nitride will be:


a. MgN
b. MgN2
c. Mg3N2
d. Mg2N3

Answer: (c)

The valency of nitride is 3 while that of magnesium is 2. Thus Mg3N2 will be the formula of the compound formed by magnesium and nitride(by crossing over the valencies).

Chhattisgarh NTSE 2021 Stage 1 SAT Question 26 solution

BIOLOGY

Question 27. Secondary consumer in the following is:


a. Cat
b. Rat
c. Foodgrains (Crops)
d. Tiger

Answer: (a)

A food chain consists of various trophic levels connected as follows:

Producers → Primary consumer → Secondary consumer → Tertiary consumer

Here, in this case, the food chain will look like:

Foodgrains (crops) → Rat → Cat → Tiger

Hence, cat is the secondary consumer.

Question 28. Lack of oxygen in muscles leads to the formation of this acid in the body:


a. Lactic Acid
b. Acetic Acid
c. Pyruvic Acid
d. Hydrochloric Acid

Answer: (a)

Lack of oxygen in the muscles results in anaerobic respiration and this leads to the formation of lactic acid.

Question 29. ‘B’ and ‘T’ Cells are:


a. Erythrocytes
b. Lymphocytes
c. Plastocytes
d. Blastocytes

Answer: (b)

Lymphocytes are a type of white blood cells present in the blood and lymph of our body. They are responsible for adaptive or acquired immunity. B and T cells are types of lymphocytes.

Question 30. The Astronauts on the moon can not talk with each other because of:


a. Very low temperature on moon
b. Very much noise on moon
c. The atmosphere on moon
d. No atmosphere on the moon

Answer: (d)

Moon does not have an atmosphere, i.e. no air. Sound can only travel in a material medium and not in vacuum, that is why astronauts cannot talk to each other on the Moon.

Question 31. Tuberculosis is:


a. Long term disease (chronic)
b. Non-contagious disease
c. Acute disease
d. Urgent disease

Answer: (a)

Tuberculosis is a chronic disease caused by bacteria and spreads from person to person through air. TB usually affects the lungs and affects for the long term (more than 3-5 months).

Question 32. In which category will you keep electronic wastes and plastics?


a. Non-biodegradable
b. Biodegradable
c. In both (a & b) Categories
d. Not in both (a & b) Categories

Answer: (a)

Electronic waste and plastics cannot be degraded by the action of natural decomposers. They are usually recycled or are incinerated. Hence, electronic waste and plastics are kept under non-biodegradable waste category.

Question 33. Hybridization method is adopted for:


a. Prevention of plants from pests
b. More production of eggs
c. Development of new irrigation methods
d. Development of species of desired characters

Answer: (d)

Hybridisation is the process of combining two genetically different varieties and producing a progeny with the desired set of characteristics.

Question 34. Main objective of family planning is:


a. Keep control on fertility rate
b. Proper gap between two child
c. Healthy mother and child
d. All of the above

Answer: (d)

Family planning ensures control on birth rate, control on fertility rates, ensures proper gaps between two children and keeps the mother and child healthy.

Question 35. ‘World ozone day’ is celebrated on:


a. 01 December
b. 16 September
c. 07 April
d. 05 June

Answer: (b)

World Ozone day is celebrated on 16th September, every year. It was designated by the United Nations General Assembly as the International Day for the Preservation of the Ozone layer.

Question 36. Which one of the following organism whose have characters of animal and plants both:


a. Euglena
b. Amoeba
c. Algae
d. Mushroom

Answer: (a)

Euglena has characters of both animals and plants. They are capable of carrying out autotrophic nutrition (photosynthesis) under sunlight due to the presence of chlorophyll and become heterotrophic in the absence of light.

Question 37. Identify the unmatched pairs:


a. Trypsin – Pancreas
b. Amylase – Saliva
c. Bile – Liver
d. Pepsin – Esophagus

Answer: (d)

Pepsin is a proteolytic enzyme produced by the peptic cells present in the gastric glands of the stomach.

Question 38. The wings of a housefly and the wings of a sparrow are an example of:


a. Analogous organ
b. Vestigial organ
c. Respiratory organ
d. Homologous organ

Answer: (a)

Analogous organs are organs that have different origins but similar functions. They are evidence for convergent evolution. Wings of housefly are made up of membranes, while wings of a sparrow are made of feathers and bones. Both of them have different origins but they both help in flight.

Question 39. Identify the unmatched pairs:


a. Cuscuta – Autotrophic
b. Plantae – Autotrophic
c. Fungi – Saprophytic
d. Animalia – Heterotrophic

Answer: (a)

Cuscuta is a parasitic plant as it lacks chlorophyll. It is a creeper and feeds on the host plant.

Question 40. The brain is responsible for:


a. Thinking
b. Regulating the heartbeat
c. Balancing the body
d. All of the above

Answer: (d)

The brain is the highest seat of coordination in the body. It does all the involuntary functions like regulating heartbeat, breathing rates, digestion etc., and voluntary functions like movement, balancing, motor-speech etc., it is the information processing, and thinking centre of the body.

MATHEMATICS


Question 41. If 9, a, b, -6 are in arithmetic progression then a + b is:


a. 1
b. 5
c. 15
d. 3

Answer: (d)

The A.P. series, 9, a, b, -6 can be expressed as 9, 9 + d, 9 + 2d, 9 + 3d respectively.

So, 9 + 3d = -6

3d = -15

d = -5

The series is

9 , 9 + (-5) , 9 + 2(-5) , 9 +3(-5)

Which is 9, 4, -1 , -6.

Comparing them with series given 9, a, b, -6, we get a + b = 4 + (-1) = 3

Question 42. If x = ay, y = bx, the value of 1 / a + 1 + 1 /1 + b =?


a. 0
b. 1
c. x + y
d. 1 / x + y

Answer: (b)

Chhattisgarh NTSE 2021 Stage 1 SAT Question 42 solutions

Question 43. If α and β are the zeros of the polynomial f(x) = x2 – 5x + k such that α – β =1, then the value of k is


a. 6
b. 2
c. 3
d. 0

Answer: (a)

For a given quadratic equation ax2 + bx + c = 0,

Sum of roots = -b / a; Product of roots = c / a

For f(x) = x2 – 5x + k

Sum of roots, α + β = -(-5) / 1

= α + β = 5……….(1)

Given: α – β = 1….(2)

Solving the equations (1) and (2), We get, α = 3, β = 2

Product of the roots, αβ = k

3 × 2 = k

K = 6

Question 44. The difference of the squares of two natural numbers is 101. The sum of their squares is equal to:


a. 5000
b. 5100
c. 5101
d. 5102

Answer: (c)

Let the two natural numbers be a and b.

Given: a2 – b2 = 101

(a + b)(a – b) = 101 x 1 (Factorising 101)

a + b = 101

a – b = 1

Solving the equations:

a = 51

b = 50

So, a2 + b2 = 512 + 502 = 2601 + 2500 = 5101

Question 45. Prashant has to pay Rs. 482 for 19 apples and 11 guavas. If he would have exchanged the number of apples and guavas purchased then he would have paid Rs. 64 less. Find how much more amount he has to pay to purchase one apple than one guava?


a. Rs. 7
b. Rs. 8
c. Rs. 11
d. Rs. 13

Answer: (b)

Let the price of 1 apple and 1 guava be ₹ x and ₹ y respectively.

From the give information:

19x + 11y = 482 …(i)

11x + 19y = (482 – 64) = 418 …(ii)

Subtracting (ii) from (i)

8x – 8y = 64

x – y = Rs. 8

The difference in prices of 1 apple and 1 guava is Rs. 8. So he has to pay ₹8 more to buy an apple than a guava.

Question 46. If x2 – x – 1 = 0 then the value of x3 – 2x + 1 is:


a. 0
b. 2
c.

\(\begin{array}{l}\frac{1+\sqrt{5}}{2}\end{array} \)

d.
\(\begin{array}{l}\frac{1+\sqrt{5}}{2}\end{array} \)

Answer: (b)

x = 1 is a root of x3 – 2x + 1 (Zero of the polynomial)

Factorising x3 – 2x + 1: x2(x – 1) + x(x – 1) – (x -1) = (x-1)(x2+x-1)

x2 = x+1 …(i)

and x2-x = 1 …(ii)

Using (i) : x2 + x – 1 = (x + 1) + x – 1 = 2x

Using (ii): x3 – 2x + 1 = (x – 1)(x2 + x – 1) = (x – 1)(2x) = 2(x2 – x) = 2(1) = 2

Question 47. In a right angled triangle the hypotenuse is to be 1 cm longer than the base and 2 cm longer than the altitude, then the perimeter of the triangle is:


a. 24 cm
b. 20 cm
c. 12 cm
d. 10 cm

Answer: (c)

Let the length of the hypotenuse be ‘a’.

So, the length of the base and altitude are (a – 1) and (a – 2) in cm, respectively.

By Pythagoras theorem, (a – 1)2 + (a – 2)2 = a2

a2 – 2a + 1 + a2 – 4a + 4 = a2

a2 – 6a + 5 = 0

a2 – 5a – a + 5 = 0

a(a – 5) – (a – 5) = 0

(a – 5)(a – 1) = 0

a = 5 (a = 1 is ignored since the other sides cannot be in negative.)

So, the sides of the right-angled triangle are 5 cm, 4 cm and 3 cm.

Perimeter of the triangle = 5 + 4 + 3 = 12 cm.

Question 48. If x% of y is equal to 1% of z, y% of z is equal to 1%, of x and z% of x is equal to 1% of y then the value of xy + yz + zx is:


a. 1
b. 2
c. 3
d. 4

Answer: (c)

Given: x% of y = 1% of z. So, xy / 100 = z / 100 ⇒ xy = z

Given: y% of z = 1% of x. So, yz / 100 = x / 100 ⇒ yz = x

Given: z% of x = 1% of y. So, zx / 100 = y / 100 ⇒ zx = y

Substituting x = yz in the equation xy = z

y2z = z ⇒ y = 1

Applying the value of y in other equations we get x = 1and z = 1

So, xy + yz + zx = 1 + 1 + 1 = 3

Note: The above solution is based on a corrected question statement.

Question 49. A tower is 100 √3m high. The angle of elevation of its top from a point 100 m away from its foot is:


a. 60o
b. 45o
c. 30o
d. 22 ½ o

Answer: (a)

Chhattisgarh NTSE 2021 Stage 1 SAT Question 49 solutions

Let the angle of elevation be ø.

Then, tanθ = Altitude / Base = 100√3/100 = √3

tanθ = √3

θ = 60o

Question 50. Two dice are thrown at the same time. Then the probability of getting the total of at least 8 is:


a. 5/6
b. 5/12
c. 5/18
d. 5/36

Answer: (b)

Total number of possible outcomes when two dice are thrown together = 6 x 6 = 36

Total of at least 8 can be obtained in the following ways:

8 – (2,6), (6,2), (3,5), (5,3), (4,4) – 5 ways

9 – (3,6), (6,3), (4,5), (5,4) – 4 ways

10 – (4,6), (6,4), (5,5) – 3 ways

11 – (5,6), (6,5) – 2 ways

12 – (6,6) – 1 way

Total number of favourable ways = 5 + 4 + 3 + 2 + 1 = 15

\(\begin{array}{l}Probability = \frac{Total \: favourable \: ways}{Total \: number \: of \: outcomes} = \frac{15}{36} = \frac{5}{12}\end{array} \)

Question 51. If the coordinate of two opposite vertices of square are (a, b) and (b, a) then the area of the square is:


a. (a+b)2
b. 2(b+a)2
c. (a-b)2
d. 2(b-a)2

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 SAT Question 51 solution

Question 52. The ratio of the volume of the cube to that of a sphere which exactly fits inside the cube is:


a. 6 : 𝜋
b. 𝜋 : 6
c. 12 : 𝜋
d. 𝜋 : 12

Answer: (a)

Let the side of the cube be “a” units.

The diameter of the sphere that exactly fits inside the cube is “a” units.

Volume of cube = a3

Volume of the sphere inscribed in the cube = 4/3𝜋(a/2)3

The volume of the cube to that of the sphere inscribed =

\(\begin{array}{l}\frac{a^{3}}{\frac{4}{3}\pi \left ( \frac{a}{2}\right )^{3}} = \frac{8\times 3}{4\pi } = \frac{6}{\pi }\end{array} \)

Hence the required ratio is 6 : 𝜋

Question 53. If any polynomial f(x) is divided by (x2 – 16) then remainder is (5x + 3). If it is divided by (x + 4) then the remainder will be:


a. 17
b. -17
c. 23
d. -23

Answer: (b)

Given that,

f(x) = Q(x2 – 16) + (5x + 3)

f(x) = Q(x + 4)(x – 4) + (5x + 3)

Dividing both sides by (x+4) as asked in the question

\(\begin{array}{l}\frac{f(x)}{x+4} = Q(x-4)+\frac{5x+3}{x+4}\end{array} \)

..…(1)

From (1) when f(x) is divided by (x + 4), reminder is

\(\begin{array}{l}\frac{(5x+3)}{x+4}\end{array} \)

Simplifying the reminder:

\(\begin{array}{l}\frac{(5x+3)}{x+4} \Rightarrow \frac{5(x+4)-17}{x+4}\end{array} \)

So, 5x + 3 = 5(x + 4) – 17

When 5x + 3 is further divided by (x + 14), we get 5 as the quotient and -17 is the reminder.

Question 54. 12 workers can build a wall in 9 days working 8 hours per day. In how many days 24 workers can build that wall working 6 hours per day?


a. 24
b. 12
c. 9
d. 6

Answer: (d)

12 workers working 8 hours per day can build a wall in 9 days.

1 worker working 1 hour per day can build a wall in 9 x 12 x 8 days.

24 workers working 6 hours per day can build a wall in

\(\begin{array}{l}\frac{9\times 12\times 8}{24\times 6}\end{array} \)
i.e 6 days.

Question 55. The ratio of medians of two similar triangles is 3 : 4. Then the ratio of their areas will be:


a. 4 : 3
b. 3 : 4
c. 16 : 9
d. 9 :16

Answer: (d)

According to corresponding parts of similar triangles, in two similar triangles, the ratio of corresponding sides is equal to the ratios of the altitudes and medians of the two triangles.

Also, if two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides or medians.

Ratio of medians =

\(\begin{array}{l}\frac{M_{1}}{M_{2}} = \frac{3}{4} =\end{array} \)
Ratio of corresponding sides

Ratio of areas =

\(\begin{array}{l}\left ( \frac{M_{1}}{M_{2}}\right )^{2} = \left ( \frac{3}{4} \right )^{2} = \frac{9}{16}\end{array} \)

Question 56. In the given figure PA = 4 cm, AB = 5 cm. Then length of PT will be:
Chhattisgarh NTSE 2021 Stage 1 SAT Question 56


a. 13 cm
b. 9 cm
c. 6 cm
d. 4 cm

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 SAT Question 56 solution

Let us draw OQ perpendicular to AB.

AQ = AB/2 = 5/2

AP + 4cm

PQ = 6.5 cm

In ΔOTP, TP2 + OT2 = OP2

In ΔOQP, OQ2 + PQ2 = OP2

OQ2 + PQ2 = OT2 + TP2

OQ2 + PQ2 = OA2 + TP2 (Since OA = OT = Radius of the circle)

OQ2– OA2 + PQ2 = TP2

Since, AO2 = AQ2 + OQ2

TP2 = -AQ2 + PQ2

TP2 = (6.5)2 – (2.5)2 = 42.25 – 6.25 = 36

TP = 6 cm

Question 57. If 69.5 is the mean of 72, 70, x, 62, 50, 71, 90, 64, 58 and 82 then the value of x will be:


a. 70
b. 72
c. 74
d. 76

Answer: (d)

Mean of the given numbers = 69.5

\(\begin{array}{l}\frac{72 + 70 + x + 62 + 50 + 71 + 90 + 64 + 58 + 82}{10} = 69.5\end{array} \)

72 + 70 + x + 62 + 50 + 71 + 90 + 64 + 58 + 82 = 695

619 + x = 695

X = 76

Question 58. In the given figure ABC is a right angled triangle with AB = 12 cm and AC = 13 cm. A circle with center O has been inscribed inside the triangle. If the radius is r then the value of r will be:


a. 1 cm
b. 1.5 cm
c. 2 cm
d. 2.5 cm

Answer: (c)

Chhattisgarh NTSE 2021 Stage 1 SAT Question 58

Given:

AB = 12 cm and AC = 13 cm

BC = 5 cm (Using pythagoras theorem)

AP = 12 – r

AR = AP = 12 – r (AR and AP are tangents from C to a circle)

BQ = BP = r

RC = QC = BC – r = 5 – r (RC and QC are tangents from C to a circle)

Ar(∆ABC) = ½ AB × BC = 30 cm2

Ar(∆ABC) = Ar(∆AOB) + Ar(∆BOC) + Ar(∆AOC)

30 = ½ [12r + 5r + 13r]

30r = 60

r = 2 cm

Question 59. The

\(\begin{array}{l}\frac{4\: cos\: 76^{o}}{3\: sin\: 14^{o}}\end{array} \)
will be:


a. 4/3
b. 3/4
c. 1
d. 0

Answer: (a)

\(\begin{array}{l}\frac{4\: cos\: 76^{o}}{3\: sin\: 14^{o}} = \frac{4\: sin\:(90 – 76)^{o}}{3\: sin\: 14^{o}} = \frac{4\: sin\: 14^{o}}{3\: sin\: 14^{o}} = \frac{4}3{}\end{array} \)

Question 60. If

\(\begin{array}{l}\frac{a^{n+1}+b^{n+1}}{a^{n}+b^{n}}\end{array} \)
is the arithmetic mean of and then value of n will be:


a. 2
b. -1
c. 1
d. 0

Answer: (d)

Arithmetic mean of two numbers a and b = (a + b)/2

Given that,

\(\begin{array}{l}\frac{a^{n+1}+b^{n+1}}{a^{n}+b^{n}} = \frac{a+b}{2}\end{array} \)

Hence, an+1 = a

n + 1 = 1

n = 0

Social Science

Question 61. Whose creation is “The Prince”?


a. ERASMUS
b. DYURAR
c. MACHIAVELLI
d. MUSSOLINI

Answer: (c)

Solution:

Niccolo Machiavelli was an Italian political thinker, he wrote ‘The Prince’ in the sixteenth century. It is an important piece of writing in modern political theory.

Question 62. When was the quit India movement?


a. 1930
b. 1935
c. 1942
d. 1943

Answer: (c)

The Quit India Movement was launched in 1942. The movement left a profound impact on the Indian freedom struggle and eventually led the country to independence.

Question 63. Who is called Gandhi of Chhattisgarh?


a. Pt. Ravishankar Shukla
b. Veer Narayan Singh
c. Pt. Sundarlal Sharma
d. Hanuman Singh

Answer: (c)

Pandit Sundarlal Sharma is known as the ‘Gandhi of Chhattisgarh’. He started the canal satyagraha and was a prominent freedom fighter from Chhattisgarh.

Question 64. Amoghvarsha was the ruler of:


a. Rashtrakuta Dynasty
b. Pallava Dynasty
c. Chandela Dynasty
d. Parmar Dynasty

Answer: (a)

Amoghvarsha was a ruler of the Rashtrakuta dynasty. He is considered as the greatest king among the Rashtrakutas. He was also a great patron of art, education and literature.

Question 65. The Gandhar school of sculpture was a blend of:


a. Indian and Greek styles
b. Indian and Persian styles
c. Was purely Indian in origin
d. Indian and South-East Asian styles

Answer: (a)

The Gandhara School of Sculpture was a blend of Indian and Greek styles of art. It flourished in areas of modern-day Afghanistan and North-Western parts of India.

Question 66. “I came I saw, I conquered was said by:


a. Napoleon
b. Changez Khan
c. Julius Caesar
d. Alexander

Answer: (c)

Julius Caesar was a Roman king. “I came, I saw, I conquered”, was announced by him on his victory over Pontus in 46 BCE.

Question 67. The country where the process of industrial revolution started first in Europe was:


a. France
b. England
c. Germany
d. Italy

Answer: (b)

The process of the industrial revolution first began in England. Inventions like the spinning jenny, power loom, steam engine and other innovations made work easier and faster.

Question 68. The “Sati Pratha” was declared illegal during the governor generalship of:


a. William Bentick
b. Dalhousie
c. Canning
d. Cornwallis

Answer: (a)

The Sati Pratha was declared illegal during Governor-General William Bentinck’s tenure. Along with Raja Rammohan Roy, he tried to suppress other social evils like polygamy, child marriage and female infanticide.

Question 69. Who was the greatest king among the ‘Cholas’:


a. Rajaraja-1
b. Aditya-1
c. Vijayraj
d. Prantika

Answer: (a)

Rajaraja Chola 1 was the greatest king among the Cholas mentioned above. He built the famous Brihadisvara Temple at Tanjore.

Question 70. Name the ruler of the Gupta dynasty about whose conquests in the Allahabad pillar inscription presents on accounts of:


a. Chandragupta Vikramaditya
b. Samudragupta
c. Kumaragupta
d. Skandagupta

Answer: (b)

The Allahabad pillar inscription presents the accounts of Samudragupta’s political and military conquests. This was composed by Harisena.

Question 71. Mesopotamia means:


a. Mesolithic culture
b. A collection of pots kept in a mess.
c. A variety of horse living along rivers
d. The land between the rivers.

Answer: (d)

The word Mesopotamia means the land between the rivers in Greek. The civilisation thrived in a valley between two rivers – Tigris and Euphrates.

Question 72. Who was the ruler of India when the Ibn Battuta visited India?


a. Ibrahim Lodhi
b. Muhammad Ghori
c. Muhammad-Bin-Tughlaq
d. Razia Sultan

Answer: (c)

Ibn Battuta was a fourteenth-century traveller who visited India from Morocco, Africa. India was under the rule of Muhammad-Bin-Tughlaq of the Delhi Sultanate during this period.

Question 73. In the northern hemisphere due to Ferrel’s law the winds deflected:


a. Towards its right
b. Towards its Left
c. Towards its North
d. Towards its South.

Answer: (a)

Solution:

The Ferrel’s law suggests that wind deflects to the right in the northern hemisphere. Similarly, in the southern hemisphere, it deflects to the left.

CHEMISTRY


Question 74. Which one of the following is the largest lake in Rajasthan:


a. Anasagar
b. Pichola
c. Sambhar
d. Udai Sagar

Answer: (c)

Sambar is the largest lake in Rajasthan. It is India’s largest inland salt lake, located 80 km southwest of the city of Jaipur.

Question 75. Which country of South America is the biggest producer of petroleum:


a. Venezuela
b. Peru
c. Chile
d. Brazil

Answer:(a)

Venezuela is the largest producer of petroleum in South America. Venezuela has a vast oil reserve estimated to be 18 % of the global reserve.

Question 76. The mediterranean sea climate is characterized by:


a. Humid Summers and dry winters
b. Humid Summers and humid winters
c. Dry Summers and dry winters
d. Dry Summers and humid winters

Answer: (d)

The Mediterranean type of climate is prevalent in the locations situated between the 30° and 45° latitude north and south of the Equator and the continents’ western margins. This type of climate is characterised by dry summers and wet or humid winters.

Question 77. From where the ‘Sri Hind’ canal takes off?


a. At Okhla near Delhi
b. From fire-lake at Khadakwasla
c. From Gomati a Banbanse
d. From Satlaj at Ruper

Answer: (d)

‘Sri Hind’ is a large irrigation canal. It takes its water from the river Sutlej, a tributary of the Indus river, at Rupar, Punjab.

Question 78. The leaves of the plants of desert forests are:


a. Pointed in shape
b. Small-sized and thorny
c. Long
d. Broad

Answer: (b)

The leaves of plants lose moisture through their pores in a process called transpiration. In desert forests, modified plant leaves become small and thorny to slow the transpiration process and retain a minimum moisture level.

Question 79. River which flows from east to west:


a. Mahanadi
b. Godavari
c. Narmada
d. Brahmaputra

Answer: (c)

The river Narmada flows from east to west. Narmada rises from Amarkantak Plateau in Madhya Pradesh. It flows through Madhya Pradesh and Gujarat and finally meets the Arabian Sea in the west.

Question 80. What kind of watermelon crop is:


a. Rabi
b. Jaid
c. Kharif
d. All of the above

Answer: (b)

Watermelon is a Jaid crop. Jaid crops are summer season crops, grown mainly during the period from March to June in India. They require warm and dry weather for their growth.

Question 81. Which one of the following is known as ‘Pittsburgh’ of India:


a. Baroda
b. Raurkela
c. Jamshedpur
d. Durgapur

Answer: (c)

Jamshedpur is known as the ‘Pittsburgh’ of India. Situated in Jharkhand, Jamshedpur is known for its steel industry.

Question 82. In which part of Africa Sahara desert is situated:


a. Northern part
b. Southern part
c. Western part
d. Eastern part

Answer: (a)

The Sahara desert is the largest desert in the world. It is located in the northern part of Africa. It covers many African countries like Algeria, Chad, Egypt, Libya, Mali, Mauritania, Morocco etc.

Question 83. The chief production in the region having black soil is:


a. Cotton
b. Rice
c. Wheat
d. Tea

Answer: (a)

Black soils are generally clayey, deep and impermeable and retain moisture for a longer period. Moreover, black soils are rich in lime, iron, magnesia and alumina, potash. This type of soil is most suitable for the production of cotton.

Question 84. The youngest folded mountain in India is:


a. Vindhyan
b. Aravallis
c. Nilgiris
d. Shiwalik

Answer: (d)

Shiwalik forms the outermost and southernmost hilly range of the Himalayas, which are the youngest fold mountains in India. They are also known as the sub-Himalayas or the foothills.

Question 85. Concept of the independent justice system in Indian constitution is abstracted from where:


a. America (U.S.A.)
b. South Africa
c. Britain
d. France

Answer: (a)

Independent justice system implies the concept that the judiciary must remain independent from other organs of the government that is the executive and the legislature. Indian Constitution derived the concept of an independent justice system from the U.S.A.

Question 86. Joint session of the Indian parliament is called by:


a. Speaker of Loksabha
b. Speaker of Rajya Sabha
c. Prime minister
d. President

Answer: (d)

A joint session of the parliament comes into existence when either of two houses (Lok Sabha or Rajya Sabha) refuses to agree on a particular matter. According to article 108 of the Indian Constitution, a joint session is called by the President of India.

Question 87. For the protection of fundamental rights writ can be issued by:


a. Only High court
b. Only Supreme court
c. Only high court and supreme court
d. Only human right commission of India

Answer: (c)

A writ is a formally written order that commands constitutional remedies for Indian Citizens against the violation of their fundamental rights. Writs are of five types in India – Habeas Corpus, Mandamus, Prohibition, Certiorari and Quo-Warranto. A writ can be issued by both the Supreme Court and High Courts of India.

Question 88. Off the following the lowest civil court is:


a. Additional Judge court
b. Nayab Tahsildar court
c. Class-III Magistrate Court
d. Court of Munsif

Answer: (d)

Chhattisgarh NTSE 2021 Stage 1 SAT Question 88

The Court of Munsif is considered to be the lowest level of civil court in India. A dispute involving property or amount which is not valued more than two thousand rupees comes within the jurisdiction of the Munsif Court.

Question 89. How the Lt. Governor of Union Territory works independently without taking a decision from the office:


a. Transport
b. Law & Order
c. Electricity
d. Civil rationing.

Answer: (b)

According to the Constitution of India, the Lieutenant Governor of a union territory can function his/her authority in matters of law and order since the subject of law and order comes under the state list.

Question 90. Who has the power to appoint and suspend the chief-election commissions?


a. Prime Minister
b. Chief Justice of Supreme Court
c. President
d. Parliament

Answer: (c)

The power to appoint and suspend the Chief Election Commissioner of India vests with the President of India. The Chief Election Commissioner is responsible for conducting free and fair elections to the national and state legislatures, to the posts of the President and Vice-President. Sunil Arora is the current 23rd Chief Election Commissioner of India.

Question 91. When was the constitution of India fully prepared?


a. 26 January, 1950
b. 26 November, 1949
c. 02 October, 1949
d. 15 November, 1949.

Answer: (b)

The Constituent Assembly drafted the Constitution of India. It was fully prepared and adopted on 26th November 1949. But the major part of it was brought into force from 26th January 1950. India celebrates 26th January as Republic day.

Question 92. How many basic duties are presently mentioned in the constitution:


a. 08
b. 11
c. 10
d. 12

Answer: (b)

The Fundamental Duties are dealt with Article 51A under Part-IV A of the Indian Constitution. The 42nd Amendment Act of 1976 added 10 Fundamental Duties to the Indian Constitution. 86th Amendment Act 2002 later added 11th Fundamental Duty to the list.

Question 93. Which is included in the capital account of the budget:


a. Income received from public borrowing
b. Income received from tax source
c. Income received from non-tax source
d. All of the above

Answer: (a)

The capital account of the budget includes capital assets and capital liabilities of the government. For example, governments’ loans or capital raised through means like borrowing comes under capital liabilities.

Question 94. What is the nature of Income Tax in India?


a. Proportional
b. Progressive
c. Regressive
d. None of the above

Answer: (b)

Progressive taxing system is one in which the population of a country pays different tax amounts at different tax rates (tax slabs) according to their income levels. For example, poor people and rich people pay different percentages of tax in India according to the income they earn.

Question 95. When was the consumer protection act enacted?


a. 1980
b. 1985
c. 1986
d. 1991

Answer: (c)

The Consumer Protection Act of 1986 was enacted to protect the interests of the consumers in terms of quality and safety of products. The Consumer Protection Act of 1986 was recently replaced with the Consumer Protection Act of 2019.

Question 96. Who determines price under perfect competition:

a. Representative firm
b. Industry
c. Normal firm
d. Government

Answer: Bonus

Perfect competition in economics means a perfect market situation where all the firms sell similar products. Under such a situation, the demand and supply forces of the market would determine the prices of the product.

Question 97. Opportunity cost of a factor is known as:


a. Transfer earning
b. Money cost
c. Present earning
d. None of the above

Answer: (a)

Opportunity cost is the profit lost by choosing an option over the next best alternative. It would be the cost paid for not choosing that alternative.

Transfer earnings are the minimum reward required to keep factors of production in its current occupation. It is the opportunity cost an individual forgoes when deciding to work in one job rather than the next best alternative. Transfer earning can also be called the opportunity cost of the factor.

Question 98. When total utility becomes maximum then the marginal utility will be:


a. Minimum
b. Average
c. Zero
d. Negative.

Answer: (c)

Total utility represents the total satisfaction experienced by a consumer from consuming a given quantity of goods and services. Whereas, marginal utility represents the value of an additional unit consumed by the consumer from a given set of goods and services. Hence marginal utility becomes zero when total utility is maximum.

Question 99. Which is the main reason for demand-pull inflation?


a. Increase in money supply
b. Increase in commercial expenditure
c. Increase in demand of foreign goods
d. All the above

Answer: (d)

Demand-pull inflation is a situation when aggregate demand is more than the aggregate supply. Such a condition arises usually due to more money with the people because of which they tend to spend more. Increase in commercial expenditure also results in more money in the hands of people. Demand in foreign goods automatically leads to an increase in its price.

Question 100. Which of the following is the largest significant factor of revenue expenditure of the central Government?


a. Defence expenditure
b. Subsidy
c. Interest payment
d. Salary

Answer: (c)

Interest payment is the largest significant factor of revenue expenditure of the central Government. Out of 1 rupee revenue expenditure, 18 paise is for interest payments.

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