Whole numbers questions are provided here, along with detailed explanations, so that students can practise these questions to improve their understanding. These questions are helpful for the students of Class 6 since whole numbers is one of the important topics for them. However, in this grade, they will learn the basic properties of whole numbers and simple arithmetic operations to be performed on them. In this article, you will learn how to solve various problems on whole numbers in simple methods and get accurate answers.
What are whole numbers?
In mathematics, whole numbers are defined as the set of numbers that include positive integers and 0. In other words, whole numbers are comprised of natural numbers and 0. The set of whole numbers is denoted by the English alphabet W.
Thus, whole numbers = W = {0, 1, 2, 3, 4, 5, 6, 7,….}
Click here to get more information about whole numbers and the properties of whole numbers.
Whole Numbers Questions and Answers
1. Write the three whole numbers occurring just before 1001.
Solution:
The three whole numbers occurring just before 1001 are 1000, 999 and 998.
2. How many whole numbers are there between 33 and 54?
Solution:
The whole numbers between 33 and 54 are:
34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53
Thus, there are 20 whole numbers between 33 and 54.
3. Find the sum by suitable rearrangement.
197 + 234 + 103
Solution:
197 + 234 + 103
This can be rearranged as:
(197 + 103) + 234
= 300 + 234
= 534
Therefore, 197 + 234 + 103 = 534.
4. The school canteen charges Rs. 20 for lunch and Rs. 4 for milk each day. How much money do you spend in 5 days on these things?
Solution:
Given,
The cost of lunch per day = Rs. 20
The cost of milk per day = Rs. 4
Cost of lunch for 5 days = 5 × Rs. 20 = Rs. 100
Cost of milk for 5 days = 5 × Rs. 4 = Rs. 20
Total cost = Rs. (100 + 20) = Rs. 120
5. Simplify: 216 × 65 + 216 × 35.
Solution:
216 × 65 + 216 × 35 = 216 × (65 + 35)
= 216 × 100
= 21600
Thus, 216 × 65 + 216 × 35 = 21600
6. Find the product by suitable rearrangement:
(a) 2 × 1768 × 50
(b) 4 × 166 × 25
Solution:
(a) 2 × 1768 × 50
This expression can be rearranged as:
= (2 × 50) × 1768
= 100 × 1768
= 176800
Therefore, 2 × 1768 × 50 = 176800
(b) 4 × 166 × 25
This expression can be rearranged as:
= (4 × 25) × 166
= 100 × 166
= 16600
Therefore, 4 × 166 × 25 = 16600
7. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres in the evening. If the milk costs Rs. 45 per litre, how much money is due to the vendor per day?
Solution:
Given,
Milk quantity supplied by a vendor in the morning = 32 litres
Milk quantity supplied by a vendor in the evening = 68 litres
The cost of milk per litre = Rs. 45
The total cost of milk per day = Rs. 45 × (32 + 68)
= Rs. 45 × 100
= Rs. 4500
Therefore, the money due to the vendor per day is Rs. 4500.
8. Evaluate: 81265 × 249 – 81265 × 149.
Solution:
81265 × 249 – 81265 × 149
This can be rearranged as:
= 81265 × (249 – 149)
= 81265 × 100
= 8126500
9. Find the product using suitable properties: 854 × 102.
Solution:
854 × 102
= 854 × (100 + 2)
= 854 × 100 + 854 × 2 (Using distributive property)
= 85400 + 1708
= 87108
Thus, 854 × 102 = 87108
10. Study the pattern:
1 × 8 + 1 = 9
12 × 8 + 2 = 98
123 × 8 + 3 = 987
1234 × 8 + 4 = 9876
12345 × 8 + 5 = 98765
Write the next two steps. Can you say how the pattern works?
(Hint: 12345 = 11111 + 1111 + 111 + 11 + 1).
Solution:
From the given, we can write the next two steps as:
123456 × 8 + 6 = 987654
1234567 × 8 + 7 = 9876543
Using the pattern 12345 = 11111 + 1111 + 111 + 11 + 1, we have:
123456 = (111111 + 11111 + 1111 + 111 + 11 + 1)
123456 × 8 = (111111 + 11111 + 1111 + 111 + 11 + 1) × 8
= 111111 × 8 + 11111 × 8 + 1111 × 8 + 111 × 8 + 11 × 8 + 1 × 8
= 888888 + 88888 + 8888 + 888 + 88 + 8
= 987648
123456 × 8 + 6 = 987648 + 6
= 987654
Yes, here the pattern works.
Now, 1234567 × 8 + 7 = 9876543
1234567 = (1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1)
1234567 × 8 = (1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) × 8
= 1111111 × 8 + 111111 × 8 + 11111 × 8 + 1111 × 8 + 111 × 8 + 11 × 8 + 1 × 8
= 8888888 + 888888 + 88888 + 8888 + 888 + 88 + 8
= 9876536
1234567 × 8 + 7 = 9876536 + 7
= 9876543
Yes, here also the pattern works.
Practice Questions on Whole Numbers
- Which is the smallest whole number?
- Evaluate the following using the distributive property of whole numbers.
4275 × 125 - Find the sum 1962 + 453 + 1538 + 647 using suitable rearrangement.
- Find the value of 24 + 27 + 16 in two different ways.
- Match the following:
(i) 425 × 136 = 425 × (6 + 30 +100) (a) Commutativity under multiplication.
(ii) 2 × 49 × 60 = 2 × 60 × 39 (b) Commutativity under addition.
(iii) 70 + 1005 + 30 = 70 + 30 + 1005 (c) Distributivity of multiplication over addition.
