ML Aggarwal Solutions for Class 8 Maths Chapter 17: Visualising Solid Shapes

ML Aggarwal Solutions for Class 8 Maths Chapter 17 Visualising Solid Shapes provide students with the basic idea of understanding solid shapes based on their views. Each question has a pictorial representation with the aim of helping students analyse the problem effortlessly. To practise the solutions regularly and gain more conceptual knowledge, students can access ML Aggarwal Solutions for Class 8 Maths Chapter 17 Visualising Solid Shapes PDF from the links given below.

Chapter 17 helps students understand the solid shapes and analyse them based on their views. The solutions are explained in simple language to help students boost their annual exam preparation, irrespective of their grasping capacity. It also provides students with the confidence to solve more complex problems within the given time frame.

ML Aggarwal Solutions for Class 8 Maths Chapter 17: Visualising Solid Shapes

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Exercise 17.1

1. Match the objects with their shapes:

Picture (object) Shape
  (i) A tent ML Aggarwal Solutions for Class 8 Chapter 17 Image 1
  1. A triangular field adjoining a square field.
  (ii) A tin ML Aggarwal Solutions for Class 8 Chapter 17 Image 2
  1. A hemispherical shell.
  (iii) A bowl ML Aggarwal Solutions for Class 8 Chapter 17 Image 3
  1. Two rectangular cross paths inside a rectangular park.
  (iv) An agricultural field ML Aggarwal Solutions for Class 8 Chapter 17 Image 4
  1. A hemisphere surmounted on a cone.
  (v) A groove ML Aggarwal Solutions for Class 8 Chapter 17 Image 5
  1. A circular path around a circular ground.
  (vi) A toy ML Aggarwal Solutions for Class 8 Chapter 17 Image 6
  1. A cylindrical shell.
  (vii) A circular park ML Aggarwal Solutions for Class 8 Chapter 17 Image 7
  1. A cone surmounted on a cylinder.
  (viii) A cross path ML Aggarwal Solutions for Class 8 Chapter 17 Image 8
  1. A cone taken out of a cylinder.

Solution:

(i) A tent – (g)

A cone surmounted on a cylinder.

(ii) A tin – (f)

A cylindrical shell.

(iii) A bowl – (b)

A hemispherical shell.

(iv) An agricultural field – (a)

A triangular field adjoining a square field.

(v) A groove – (h)

A cone taken out of a cylinder.

(vi) A toy – (d)

A hemisphere surmounted on a cone.

(vii) A circular park – (e)

A circular path around a circular ground.

(viii) A cross path – (c)

Two rectangular cross paths inside a rectangular park.

2. For each of the given solids, the two views are given. Match for each solid the corresponding front and top views.

ML Aggarwal Solutions for Class 8 Chapter 17 Image 9

ML Aggarwal Solutions for Class 8 Chapter 17 Image 10

ML Aggarwal Solutions for Class 8 Chapter 17 Image 11

Solution:

Object Front View Top View
  a. A bottle (iii) (y)
  b. A funnel (i) (v)
  c. A flash (ii) (u)
  d. A shuttle cock (vi) (x)
  e. A box (iv) (z)
   f. A weight (v) (w)

3. For the given solid, identify the front, side and top views and write it in the space provided.

ML Aggarwal Solutions for Class 8 Chapter 17 Image 12

Solution:

ML Aggarwal Solutions for Class 8 Chapter 17 Image 13

4. For each of the given solids, the three views are given. Identify for each solid the corresponding top, front and side views.

ML Aggarwal Solutions for Class 8 Chapter 17 Image 14

ML Aggarwal Solutions for Class 8 Chapter 17 Image 15

ML Aggarwal Solutions for Class 8 Chapter 17 Image 16

Solution:

Object Different Views

(a) An inkpot

(i) Front

(ii) Side

(iii) Top

(b) A gas stove

(i) Front

(ii) Top

(iii) Side

(c) A brick

(i) Top

(ii) Front

(iii) Side

(d) A container

(i) Front

(ii) Side

(iii) Top

(e) Almirah

(i) Side

(ii) Top

(iii) Front

(f) A matchbox

(i) Side

(ii) Front

(iii) Top

5. For each given solid, identify the top view, front view and side view.

ML Aggarwal Solutions for Class 8 Chapter 17 Image 17

ML Aggarwal Solutions for Class 8 Chapter 17 Image 18

ML Aggarwal Solutions for Class 8 Chapter 17 Image 19

Solution:

(a)

(i) Top view

(ii) Side view

(iii) Front view

(b)

(i) Side view

(ii) Front view

(iii) Top view

(c)

(i) Top view

(ii) Side view

(iii) Front view

(d)

(i) Side view

(ii) Front view

(iii) Top view

(e)

(i) Front view

(ii) Top view

(iii) Side view

6. Draw the front view, side view and top view of the given objects:

ML Aggarwal Solutions for Class 8 Chapter 17 Image 20

ML Aggarwal Solutions for Class 8 Chapter 17 Image 21

Solution:

ML Aggarwal Solutions for Class 8 Chapter 17 Image 22

ML Aggarwal Solutions for Class 8 Chapter 17 Image 23

Exercise 17.2

1. Can a polyhedron have for its faces

(i) 3 triangles?

(ii) 4 triangles?

(iii) a square and four triangles?

Solution:

(i) No

(ii) Yes

(iii) Yes

2. Which are prisms among the following?

ML Aggarwal Solutions for Class 8 Chapter 17 Image 24

Solution:

(i) and (iv) are the only prisms.

3. Verify Euler’s formula for these solids:

ML Aggarwal Solutions for Class 8 Chapter 17 Image 25

Solution:

Faces Vertices Edges F + V = E + 2
(i) 7 10 15 7 + 10 = 15 + 2

17 = 17

(ii) 9 5 12 9 + 5 = 12 + 2

14 = 14

(iii) 7 7 12 7 + 7 = 12 + 2

14 = 14

(iv) 9 9 16 9 + 9 = 16 + 2

18 = 18

4. Can a polyhedron have 15 faces, 30 edges and 20 vertices?

Solution:

We know that

F + V = E + 2

Substituting the values

15 + 20 = 35 and 30 + 2 = 32

Here

35 ≠ 32

Therefore, a polyhedron cannot have 15 faces, 30 edges and 20 vertices.

5. If a polyhedron has 8 faces and 8 vertices, find the number of edges.

Solution:

We know that

A polyhedron has 8 faces and 8 vertices.

Here

No. of edges = F + V – 2

Substituting the values

= 8 + 8 – 2

= 14

6. If a polyhedron has 7 faces and 10 vertices, find the number of edges.

Solution:

We know that

A polyhedron has 7 faces and 10 vertices

Here

No. of edges = F + V – 2

Substituting the values

= 7 + 10 – 2

= 15

7. Write the number of faces, vertices and edges in

(i) an octagonal prism

(ii) decagonal pyramid.

Solution:

No. of Faces No. of Vertices No. of Edges
(i) an octagonal prism 10 16 24
(ii) decagonal pyramid 11 11 20

8. Using Euler’s formula, complete the following table:

Faces Vertices Edges
(i) 6 12
(ii) 5 8
(iii) 14 24
(iv) 16 30
(v) 16 42
(vi) 19 19

Solution:

Faces Vertices Edges F + V = E + 2
(i) 6 8 12 12 + 2 = 14

6 + 8 = 14

(ii) 5 5 8 8 + 2 = 10

5 + 5 = 10

(iii) 14 24 36 14 + 24 = 38

38 – 2 = 36

(iv) 16 16 30 30 + 2 = 32

16 + 16 = 32

(v) 16 28 42 42 + 2 = 44

16 + 28 = 44

(vi) 19 19 36 19 + 19 = 38

2 + 36 = 38

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