NCERT Exemplar Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability

The NCERT Exemplar Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability are important for students, as it helps them to get acquainted with the different variations of questions and, thus, develop their problem-solving abilities. Students can make use of the NCERT Exemplar Solutions available subject-wise to get assistance in solving the exercise problems in every chapter. These solutions are developed by following the latest CBSE syllabus and guidelines so that students can score good marks in the Class 12 board exam.

Continuity and Differentiability is the 5th chapter of NCERT Exemplar for Class 12. This is an important chapter as it lays a foundation for the concept of Differential Calculus. The topics covered in this chapter are continuity, differentiability, algebra of continuous functions, derivatives of composite functions, implicit functions and inverse trigonometric functions, exponential and logarithmic functions, logarithmic differentiation, derivatives of functions in parametric forms, second-order derivative and mean value theorem. The solutions to the exercise problems for this chapter are available in PDF and NCERT Exemplar Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability and can be accessed by the students from the link given below.

Download the PDF of NCERT Exemplar Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability

 

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Access Answers to NCERT Exemplar Class 12 Maths Chapter 5 Continuity and Differentiability

Exercise 5.3 Page No: 107

Short Answer (S.A.)

1. Examine the continuity of the function f (x) = x3 + 2x2 – 1 at x = 1

Solution:

We know that, y = f(x) will be continuous at x = a if,

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 1

Thus, f(x) is continuous at x = 1.

 

Find which of the functions in Exercises 2 to 10 is continuous or discontinuous at the indicated points:

2.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 2 at x = 2

Solution:

Checking the continuity of the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 3

Thus, f(x) is discontinuous at x = 2.

3.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 4 at x = 0

Solution:

Checking the right hand and left hand limits of the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 5

Therefore, the given function f(x) is discontinuous at x = 0.

4.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 6 at x = 2

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 7

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 8

Thus, f(x) is continuous at x = 2.

5.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 9 at x = 4

Solution:

Checking the right hand and left hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 10

Thus, f(x) is discontinuous at x = 4.

6.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 11 at x = 0

Solution:

Checking the right hand and left hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 12

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 13

Thus, the given function f(x) is continuous at x = 0.

7.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 14 at x = a

Solution:

Checking the right hand and left hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 15

Thus, the given function f(x) is continuous at x = 0.

8.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 16 at x = 0

Solution:

Checking the right hand and left hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 17

Thus, f(x) is discontinuous at x = 0.

9.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 18 at x = 1

Solution:

Checking the right hand and left hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 19

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 20

Thus, the given function f(x) is continuous at x = 1.

10. f (x) = |x| + |x – 1| at x = 1

Solution:

Checking the right hand and left hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 21

Thus, f(x) is continuous at x = 1.

Find the value of k in each of the Exercises 11 to 14 so that the function f is continuous at the indicated point:

11.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 22

Solution:

Finding the left hand and right hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 23

So,

7 = 2k

k = 7/2 = 3.5

Therefore, the value of k is 3.5

12.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 24

Solution:

The given function f(x) can be rewritten as,

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 25

So, k = ½

Therefore, the value of k is ½

13.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 26

Solution:

Finding the left hand and right hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 27

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 28

Therefore, the value of k is -1

14.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 29

Solution:

Finding the left hand and right hand limits for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 30

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 31

Therefore, the value of k is ± 1

15. Prove that the function f defined by

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 31

remains discontinuous at x = 0, regardless the choice of k.

Solution:

Finding the left hand and right hand limit for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 32

Now, as the left hand limit and the right hand limit are not equal and the value of both the limits are constant.

Hence, regardless the choice of k, the given function remains discontinuous at x = 0.

16. Find the values of a and b such that the function f defined by

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 33

is a continuous function at x = 4.

Solution:

Finding the left hand and right hand limit for the given function, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 34

So, -1 + a = a + b = 1 + b

-1 + a = a + b and 1 + b = a + b

We get, b = -1 and 1 + -1 = a + -1 ⇒ a = 1

Therefore, the value of a = 1 and b = -1

17. Given the function f (x) = 1/(x + 2) . Find the points of discontinuity of the composite function

y = f (f (x)).

Solution:

Given,

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 35

Now, the function will not be defined and continuous where

2x + 5 = 0 ⇒ x = -5/2

Therefore, x = -5/2 is the point of discontinuity.

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 36

18. Find all points of discontinuity of the function

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 37

Now,

if f(t) is discontinuous, then 2 – x = 0 ⇒ x = 2

And, 2x – 1 = 0 ⇒ x = ½

Therefore, the required points of discontinuity for the given function are 2 and ½.

19. Show that the function f (x) = |sin x + cos x| is continuous at x = p. Examine the differentiability of f, where f is defined by

Solution:

Given,

f(x) = |sin x + cos x| at x = π

Now, put g(x) = sin x + cos x and h(x) = |x|

Hence, h[g(x)] = h(sin x + cos x) = |sin x + cos x|

Now,

g(x) = sin x + cos x is a continuous function since sin x and cos x are two continuous functions at x = π.

We know that, every modulus function is a common function is a continuous function everywhere.

Therefore, f(x) = |sin x + cos x| is continuous function at x = π.

20.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 38at x = 2.

Solution:

We know that, a function f is differentiable at a point ‘a’ in its domain if

Lf’(c) = Rf’(c)

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 39

Therefore, f(x) is not differentiable at x = 2.

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 40

21.

Solution:

Given,

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 41

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 42

Therefore, f(x) is differentiable at x = 0

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 43

22.

Solution:

We know that, f(x) is differentiable at x = 2 if

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 44

Thus, f(x) is not differentiable at x = 2.

23. Show that f (x) = |x – 5| is continuous but not differentiable at x = 5.

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 45

Therefore, f(x) is not differentiable at x = 5.

24. A function f : R ® R satisfies the equation f ( x + y) = f (x) f (y) for all x, y ÎR, f (x) ¹ 0. Suppose that the function is differentiable at x = 0 and f ¢ (0) = 2. Prove that f ¢(x) = 2 f (x).

Solution:

Given,

f : R ® R satisfies the equation f ( x + y) = f (x) f (y) for all x, y ÎR, f (x) ¹ 0

Let us take any point x = 0 at which the function f(x) is differentiable.

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 46

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 47

Therefore, f’(x) = 2f(x).

Differentiate each of the following w.r.t. x (Exercises 25 to 43) :

25. NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 48

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 49

26.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 50

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 51

27. NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 52

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 53

28.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 54

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 55

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 56

29.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 57

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 58

30. sinn (ax2 + bx + c)

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 59

31.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 60

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 61

32. sin x2 + sin2 x + sin2 (x2)

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 62

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 62

33.

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 63

34. (sin x)cos x

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 64

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 65

35. sinm x . cosn x

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 66

36. (x + 1)2 + (x + 2)3 + (x + 3)4

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 67

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 68

37.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 69

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 70

38.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 71

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 72

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 73

39.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 74

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 75

40.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 76

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 77

41.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 78

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 79

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 80

42.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 81

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 82

43.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 83

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 84

Find dy/dx of each of the functions expressed in parametric form in Exercises from 44 to 48.

44.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 85

Solution:

Given,

x = t + 1/t, y = t – 1/t

Differentiating both the parametric functions w.r.t θ

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 86

45.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 87

Solution:

Given,

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 88

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 89

46. x = 3cosq – 2cos3q, y = 3sinq – 2sin3q.

Solution:

Given, x = 3cosq – 2cos3q, y = 3sinq – 2sin3q.

Differentiating both the parametric functions w.r.t. q

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 90

47.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 91

Solution:

Given,

sin x = 2t/(1 + t2), tan y = 2t/ (1 – t2)

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 92

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 93

48.
NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 94

Solution:

On differentiating both the given parametric functions w.r.t. t, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 95

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 96

49. If x = ecos2t and y = esin2t, prove that dy/ dx = y log x/ x log y.

Solution:

Given,

x = ecos2t and y = esin2t

So, cos 2t = log x and sin 2t = log y

Now, differentiating both the parameter functions w.r.t t, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 97

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 98

50. If x = asin2t (1 + cos2t) and y = b cos2t (1–cos2t), show that

Solution:

Given,

x = asin2t (1 + cos2t) and y = b cos2t (1–cos2t)

Differentiating both the parametric equations w.r.t t, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 99

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 100

51. If x = 3sint – sin 3t, y = 3cost – cos 3t, find

Solution:

Given,

x = 3sint – sin 3t, y = 3cost – cos 3t

Now, differentiating both the parametric functions w.r.t t, we have

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 101

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 102

52. Differentiate x/sinx w.r.t sin x.

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 103

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 104

53. Different w.r.t tan-1 x when x ≠ 0.

Solution:

NCERT Exemplar Solutions Class 12 Mathematics Chapter 5 - 105

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