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Question
The condition for erythroblastosis foetalis to occur is
The condition for erythroblastosis foetalis to occur is
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Solution
The correct option is A Rh -ve mother and Rh +ve baby
The correct option is A
Explanation for correct option:
- Erythroblastosis fetalis results from Rh incompatibility, which may develop if a woman with Rh -ve blood conceives a fetus with Rh +ve blood.
- At the time of delivery, some blood cells of the baby usually enter the mother’s bloodstream.
- The mother’s immune system will produce antibodies against the Rh antigen, which can attack the fetal RBCs having the Rh factor during the next pregnancy.
Explanation for incorrect options:
Option B:
This is not the perfect condition for erythroblastosis fetalis.
Option C:
This is not the perfect condition for erythroblastosis fetalis.
Option D:
This is not the perfect condition for erythroblastosis fetalis.
Final Answer: The condition for erythroblastosis fetalis to occur is Rh -ve mother and Rh +ve baby.
Rh -ve mother and Rh +ve baby
The correct option is A
Explanation for correct option:
- Erythroblastosis fetalis results from Rh incompatibility, which may develop if a woman with Rh -ve blood conceives a fetus with Rh +ve blood.
- At the time of delivery, some blood cells of the baby usually enter the mother’s bloodstream.
- The mother’s immune system will produce antibodies against the Rh antigen, which can attack the fetal RBCs having the Rh factor during the next pregnancy.
Explanation for incorrect options:
Option B:
This is not the perfect condition for erythroblastosis fetalis.
Option C:
This is not the perfect condition for erythroblastosis fetalis.
Option D:
This is not the perfect condition for erythroblastosis fetalis.
Final Answer: The condition for erythroblastosis fetalis to occur is Rh -ve mother and Rh +ve baby.
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