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(√11 – √7) / (√11 + √7) = a – √77 b. Find a and b.

On rationalizing the LHS,\(\begin{array}{l}\frac{\sqrt{11}-\sqrt{7}}{\sqrt{11}+\sqrt{7}}\\ =\frac{\sqrt{11}-\sqrt{7}}{\sqrt{11}+\sqrt{7}} \times \frac{\sqrt{11}-\sqrt{7}}{\sqrt{11}-\sqrt{7}} \\ =\frac{(\sqrt{11}-\sqrt{7})^{2}}{(\sqrt{11}+\sqrt{7})(\sqrt{11}-\sqrt{7})} \\ =\frac{(\sqrt{11})^{2}+(\sqrt{7})^{2}-2(\sqrt{11})(\sqrt{7})}{(\sqrt{11})^{2}-(\sqrt{7})^{2}} \\ =\frac{11+7-2 \sqrt{77}}{11-7} \\ =\frac{18-2 \sqrt{77}}{4} \\ =\frac{18}{4}-\frac{2}{4} \sqrt{77}... View Article