The greatest common factor of given numbers is called
The greatest common factor of given numbers is called HCF.
The greatest common factor of given numbers is called HCF.
Let the age of Raju be x years. The age of Ritu will be = 4 × x years In... View Article
Take, n = 45, choose any starting value of x. \(\begin{array}{l}3^{3} = 27<45\\ x=3\\ \mathrm{x}_{\mathrm{next}}=\frac{2}{3} \mathrm{x}+\frac{\mathrm{n}}{3 \mathrm{x}^{2}}\\ \mathrm{x}_{\mathrm{next}}=\frac{2}{3} 3+\frac{45}{3 \times... View Article
No. Consider the positive integer 3q + 1, where q is a natural number. => (3q + 1)2 = 9q2... View Article
The equation of hyperbola required is \(\begin{array}{l}\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1 \ldots(1) \text { a and b are parameters}\\ \text { Differentiating w.r.t }\mathrm{x},... View Article
The degree of the monomial 3mn is 2.
Let Kiran’s age be x years. So, the age of Suresh = 2x years x + 2x = 24 ⇒... View Article
Let the third number be x. \(\begin{array}{l}\text \ First \ number =x-\frac{30 x}{100}\\ =\frac{100 x-30 x}{100}=\frac{70 x}{100}=\frac{7 x}{10}\\ \text \... View Article
Consider \(\begin{array}{l}\tan \left(\frac{5 \pi}{6}\right)=\tan \left(\pi-\frac{\pi}{6}\right) \\ =-\tan \frac{\pi}{6} \\ =-\frac{1}{\sqrt{3}} \\ \cos \left(13 \frac{\pi}{6}\right)=\cos \left(2 \pi+\frac{\pi}{6}\right) \\ =\tan ^{-1}\left(\frac{-1}{\sqrt{3}}\right)+\cos ^{-1}\left(\frac{\sqrt{3}}{2}\right)... View Article
tan theta can be expressed as \(\begin{array}{l}\tan \theta=\frac{\sin \theta}{\cos \theta}=\frac{\sin \theta}{\sqrt{1-\sin ^{2} \theta}}\end{array} \)
7 * 8 = 56 – 7 = 49. 4 * 4 = 16 – 4 = 12. 6 *... View Article
Point (1, 2) lies in the first quadrant. Point (- 2, 4) lies in the second quadrant. Point (- 3,... View Article
Volume of the old cone = volume of the new cone \(\begin{array}{l}\frac{1}{3} \pi \times r_{1}^{2} h_{1}=\frac{1}{3} \pi \times r_{2}^{2} h_{2}... View Article
The natural number which is a multiple of every number is 1.
The nth term of the given sequence is \(\begin{array}{l}\mathrm{t}_{\mathrm{n}}=-103 \\ \mathrm{a}=37, \mathrm{~d}=32-37=-5 \\ -103=37+(\mathrm{n}-1)(-5) \\ =37-5 \mathrm{n}+5 \\ 5 \mathrm{n}=145... View Article
He earns Rs. 25440 per month. \(\begin{array}{l}\text { Rent }=\frac{1}{4} \times 25440=6360 \Rightarrow \frac{6360}{25440} \times 360=90^{\circ}\\ \text { Food and... View Article
They are equal when \(\begin{array}{l}^{\mathrm{n}} \mathrm{P}_{\mathrm{r}}={ }^{\mathrm{n}} \mathrm{C}_{\mathrm{r}} \\ \frac{\mathrm{n} !}{(\mathrm{n}-\mathrm{r}) !}=\frac{\mathrm{n} !}{(\mathrm{n}-\mathrm{r}) ! \cdot \mathrm{r} !} \\ \mathrm{r} !=1... View Article
Let the direction ratios of the normal of the required plane be a, b, c. The plane is parallel to... View Article
64000 is not a perfect square as the number of zeroes are odd.
From the question, \(\begin{array}{l}n_{1}=10, \bar{x}_{1}=30, n_{2}=20, \bar{x}_{2}=15 \\ \Rightarrow \bar{x}_{12}=\frac{n_{1} \bar{x}_{1}+n_{2} \bar{x}_{2}}{n_{1}+n_{2}}=\frac{10 \times 30+20 \times 15}{10+20} \\ =\frac{600}{30}\\=20\end{array} \)