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If [latex]\vec{a}[/latex], [latex]\vec{b}[/latex], [latex]\vec{c}[/latex] are three mutually perpendicular vectors equally inclined to [latex]\vec{a}+\vec{b}+\vec{c}[/latex] at angle θ, then find the value of 36 cos2 2θ.

Answer: 4 \(\begin{array}{l}\vec{a}.\vec{b} = \vec{b}.\vec{c}=\vec{c}.\vec{a}=0\end{array} \) \(\begin{array}{l}(\vec{a}+\vec{b} +\vec{c}). (\vec{a}+\vec{b} +\vec{c})= \left | \vec{a} +\vec{b}+\vec{c}\right |^{2}\end{array} \) \(\begin{array}{l}\left | \vec{a} \right... View Article