Latest Posts

Solve the equations 2x4 + x3 – 6x2 + x + 2 = 0.

The given equation is \(\begin{array}{l}2 x^{4}+x^{3}-6 x^{2}+x+2=0\\ \text { Dividing by } \mathrm{x}^{2}, \Rightarrow 2 x^{2}+x-6+\frac{1}{x}+\frac{2}{x^{2}}=0\\ \Longrightarrow 2\left(x^{2}+\frac{1}{x^{2}}\right)+\left(x+\frac{1}{x}\right)-6=0 \Longrightarrow 2\left(x+\frac{1}{x}\right)^{2}+\left(x+\frac{1}{x}\right)-10=0\\... View Article

Differentiate the following w.r.t. x: cosec-1 (e-x).

Answer: Let y = cosec–1(e–x) Differentiate the above equation with respect to x, we get \(\begin{array}{l}\frac{dy}{dx}=\frac{d}{dx}\left[{cosec}^{-1}\left({e}^{-{x}}\right)\right]\end{array} \). ⇒ \(\begin{array}{l}\frac{-1}{{e}^{-{x}} \sqrt{\left({e}^{-{x}}\right)^{2}-1}}... View Article