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Which of the following is the unit vector perpendicular to [latex]vec{A}[/latex] and [latex]vec{B}[/latex]?

1) \(\begin{array}{l}\frac{\hat{A}\times \hat{B}}{ABsin\theta }\end{array} \) 2) \(\begin{array}{l}\frac{\hat{A}\times \hat{B}}{ABcos\theta }\end{array} \) 3) \(\begin{array}{l}\frac{\vec{A}\times \vec{B}}{ABsin\theta }\end{array} \) 4) \(\begin{array}{l}\frac{\vec{A}\times \vec{B}}{ABcos\theta }\end{array} \) Answer: 3) \(\begin{array}{l}\frac{\vec{A}\times \vec{B}}{ABsin\theta }\end{array} \)... View Article

Two forces F1 = 1 N and F2 = 2 N act along the lines x =0 and y =0 respectively. Then, the resultant of forces would be

1) \(\begin{array}{l}\hat{i}+2\hat{j}\end{array} \) 2) \(\begin{array}{l}\hat{i}+\hat{j}\end{array} \) 3) \(\begin{array}{l}3\hat{i}+2\hat{j}\end{array} \) 4) \(\begin{array}{l}2\hat{i}+\hat{j}\end{array} \) Answer: 4) \(\begin{array}{l}2\hat{i}+\hat{j}\end{array} \) Solution: x = 0 means y-axis ⇒ \(\begin{array}{l}\vec{F_{1}}=\hat{j}\end{array} \) y = 0... View Article

A particle acted upon by constant forces [latex]4hat{i}+hat{j}-3hat{k}[/latex] and [latex]3hat{i}+hat{j}-hat{k}[/latex] is displaced from the point [latex]hat{i}+2hat{j}-3hat{k}[/latex] to point [latex]5hat{i}+4hat{j}-hat{k}[/latex]. The total work done by the forces in SI unit is

1) 20 2) 24 3) 50 4) 30 5) 35 Answer: 2) 24 Solution: \(\begin{array}{l}F_{1}=4\hat{i}+\hat{j}-3\hat{k}\end{array} \) \(\begin{array}{l}F_{2}=3\hat{i}+\hat{j}-\hat{k}\end{array} \)   \(\begin{array}{l}F_{1}+F_{2}= (4\hat{i}+\hat{j}-3\hat{k})... View Article

the angle between the vectors a and b

1) cos-1(-1/3) 2) cos-1(1/4) 3) cos-1(-1/2) 4) cos-1(-1/6) Answer: 1) cos-1(-1/3) Solution: Angle between vectors \(\begin{array}{l}a = 3\hat{i}-4\hat{j}\end{array} \) and \(\begin{array}{l}b = 2\hat{i}+3\hat{k}\end{array} \), \(\begin{array}{l}a... View Article

The (x, y, z) coordinates of two points A and B are given respectively, as (0, 3, –1) and (–2, 6, 4). The displacement vector from A to B may be given by

1) \(\begin{array}{l}-2\hat{i}+6\hat{j}+4\hat{k}\end{array} \) 2) \(\begin{array}{l}-2\hat{i}+3\hat{j}+3\hat{k}\end{array} \) 3) \(\begin{array}{l}-2\hat{i}+3\hat{j}+5\hat{k}\end{array} \) 4) \(\begin{array}{l}2\hat{i}+3\hat{j}-5\hat{k}\end{array} \) Answer: 3) \(\begin{array}{l}-2\hat{i}+3\hat{j}+5\hat{k}\end{array} \) Solution: Displacement vector \(\begin{array}{l}r_{i}= 3\hat{j}-\hat{k}\end{array} \) \(\begin{array}{l}r_{i}=-2\hat{i}+6\hat{j}+4\hat{k}\end{array} \) \(\begin{array}{l}r_{f}-r_{i}=\Delta r=(-2\hat{i}+6\hat{j}+4\hat{k})-(3\hat{j}-\hat{k})\end{array}... View Article

The magnitude of a vector on the addition of two vectors [latex]6\hat{i}+7\hat{j}[/latex] and [latex]3\hat{i}+4\hat{j}[/latex]

1) \(\begin{array}{l}\sqrt{132}\end{array} \) 2) \(\begin{array}{l}\sqrt{136}\end{array} \) 3) \(\begin{array}{l}\sqrt{160}\end{array} \) 4) \(\begin{array}{l}\sqrt{202}\end{array} \) Answer: 4) \(\begin{array}{l}\sqrt{202}\end{array} \) Solution: \(\begin{array}{l}A= 6\hat{i}+7\hat{j}\end{array} \) and \(\begin{array}{l}B= 3\hat{i}+4\hat{j}\end{array} \) Sum of two... View Article

Three vectors [latex]vec{a}[/latex],[latex]vec{b}[/latex] and [latex]vec{c}[/latex] satisfy the relation [latex]vec{a}.vec{b}=0[/latex] and [latex]vec{a}.vec{c}=0[/latex]. The vector [latex]vec{a}[/latex] is parallel to

1) \(\begin{array}{l}\vec{b}\end{array} \) 2) \(\begin{array}{l}\vec{c}\end{array} \) 3) \(\begin{array}{l}\vec{b}.\vec{c}\end{array} \) 4) \(\begin{array}{l}\vec{b}\times \vec{c}\end{array} \) Answer: 4) \(\begin{array}{l}\vec{b}\times \vec{c}\end{array} \) Solution: \(\begin{array}{l}\vec{a}. \vec{b}=0\end{array} \) i.e., \(\begin{array}{l}\vec{a}\end{array} \) and \(\begin{array}{l}\vec{b}\end{array} \)... View Article

In a clockwise system

1) \(\begin{array}{l}\hat{j}\times \hat{k}=\hat{i}\end{array} \) 2) \(\begin{array}{l}\hat{i}.\hat{i}= 0\end{array} \) 3) \(\begin{array}{l}\hat{j}\times \hat{j}= 1\end{array} \) 4) \(\begin{array}{l}\hat{k}.\hat{j}= 1\end{array} \) Answer: 1) \(\begin{array}{l}\hat{j}\times \hat{k}=\hat{i}\end{array} \) Solution: In a clockwise... View Article