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Solve the equation 3(2^x1)-2x^2+5=0

Given: 3(2<sup>x</sup>+1)-2<sup>x+2</sup>+5=0 Solution: 3(2<sup>x</sup>+1)-2<sup>x+2</sup>+5=0 3×2<sup>x</sup>+3-2<sup>x</sup>×2<sup>2</sup>+5=0 3×2<sup>x</sup>-4×2<sup>x</sup>+8=0 (3-4)×2<sup>x</sup>+8=0 -2<sup>x</sup>+8=0 2<sup>x</sup>=8 2<sup>x</sup>=2<sup>3</sup> x=3