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Solve 1-(x-2)-(x-3)-(x-1)=0

Given: To solve: 1-(x-2)-[(x-3)-(x-1)] = 0 Solution: 1-(x-1)-[(x-3)-(x-1)]=0 1-(x-2)-[(x-3-x+1)]=0 1-(x-2)-[(-2)]=0 1-(x-2)+2=0 1-x+2+2=0 x=5