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Which of the following is dimensionless?

1) v2/rg 2) v2g/r 3) vg/r 4) v2rg Answer: 1) v2/rg Solution: \(\begin{array}{l}\frac{v^{2}r}{g}=\frac{(L^{1}T^{-1})^{2}L^{1}}{LT^{-2}}=L^{2}\end{array} \) \(\begin{array}{l}\frac{v^{2}}{rg}=\frac{(L^{1}T^{-1})^{2}}{L^{1}LT^{-2}}=M^{0}L^{0}T^{0}\end{array} \) \(\begin{array}{l}\frac{v^{2}g}{r}=\frac{(L^{1}T^{-1})^{2}LT^{-2}}{L^{1}}=L^{2}T^{-4}\end{array} \) \(\begin{array}{l}v^{2}rg =(L^{1}T^{-1})^{2}LT^{-2}L^{1}= L^{4}T^{-3}\end{array}... View Article