a) (0, π/4) b) (0, π/2) c) (0, 3π/4) d) (π/4, 3π/4) Solution: L11×L22 >0 sinθ +cosθ > 1 θ... View Article
Let S be the sum of the first 9 terms of the series: {x+ka}+{x2+(k+2)a}+{x3+(k+4)a}+{x4+(k+6)a}+… where a ≠ 0 and a... View Article
a) (0,1) b) (1,3) c) (-1,0) d) (-3,-1) Solution: Let f(x) = a (x-3) (x-α) f(-1)+f(2) = 0 a[(-1-3) (-1-α)+(2-3)(2-α)]... View Article
Which of the following is a tautology? a) (p→q) ˄( q→p) b) (~p) ˄(p ˅q)→q c) (q→p) ˅~(p→q) d) (~q)˅(... View Article
a) increases in (-1, ∞) b) decreases in (-1,0) and increases in (0, ∞) c) increases in (-1,0) and decreases... View Article
Consider a region R = {(x,y)∈R2 : x2 ≤y ≤ 2x}. If a line y = α divides the area... View Article
a) y+4x = 2 b) 2y+x = 4 c) x+4y = 8 d) y = 4x+2 Solution: At x =... View Article
Let A = {X= (x,y,z)T: PX = 0 and x2+y2+z2 = 1}, where P = \(\begin{array}{l}\begin{bmatrix} 1 & 2 &... View Article
a) -5 b) 10 c) 5 d) -10 Solution: Required plane is \(\begin{array}{l}\begin{vmatrix} x-3 &y-1 & z-1\\ 1& -2& 2\\... View Article
a) √6 b) -2√6 c) 6 d) -√6 Solution: (3+2i√54)1/2-(3-i2√54)1/2 = (9+6i2+2×3i√6)1/2-(9+6i2-2×3i√6)1/2 = ((3+√6i)2)1/2 -((3-√6i)2)1/2 = (3+√6i)( 3-√6i) = -2√6i... View Article
a) 128√3 b) 192√3 c) 64√3 d) 256√3 Solution: A: (a cos 300, a sin 300) lies on parabola (a2/4)... View Article
a) (-1/2, -1/4] b) [-1,-1/2] c) [-3/2, -5/4] d) (-5/4, -1) Solution: cos4θ+sin4θ+λ = 0 λ = -{1-(1/2)sin22θ} 2(λ+1) =... View Article
Let EC denote the complement of an event E. Let E1, E2 and E3 be any pair wise independent events... View Article
If the sum of first 11 terms of an A.P, a1,a2,a3… is 0 (a1 ≠ 0) then the sum of... View Article
Solution: Tangent at (c, ec) y-ec = ec(x-c) ….(i) normal to parabola y-2 = -1(x-1) x+y = 3 …(ii) At... View Article
Solution: Let xyz be 3 digit number x+y+z = 10 where x ≥1, y ≥0, z ≥0 x-1≥0 Put x-1... View Article
Let S be the set of all integer solutions, (x, y, z), of the system of equations x-2y+5z = 0... View Article
Let a plane P contain two lines \(\begin{array}{l}\vec{r} = \hat{i}+\lambda (\hat{i}+\hat{j})\end{array} \) , λ ∈ R and \(\begin{array}{l}\vec{r} = -\hat{j}+\mu... View Article
Solution: Let 3 consecutive coefficients are nCr-1 : nCr : nCr+1::2:5:12 nCr-1/ nCr = 2/5 and nCr/ nCr+1 = 5/12... View Article