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Find the value of (243)1/5

\(\begin{array}{l}243^{\frac{1}{5}}\end{array} \) = \(\begin{array}{l}(3^{5})^{\frac{1}{5}}\end{array} \) = \(\begin{array}{l}3^{1}\end{array} \) =3

The density of mercury is 136 gmcc convert it into si units

Dimensions of Density are ML−3 1 kg=1000 g,1 m=100 cm Thus, 13.6 g/cc=\(\begin{array}{l}=13.6 (1000^{-1})(100^{-1})^{-1}\end{array} \) \(\begin{array}{l}=13.6*10^{-3}*10^{6}\end{array} \) \(\begin{array}{l}=13.6*10^{3} kg/m^{3}\end{array} \)

Factorise 25÷4 x^2-y^2÷9

Answer: \(\begin{array}{l}\frac{25}{4}x^{2} – \frac{y^{2}}{9}\end{array} \) = \(\begin{array}{l}\frac{25x^{2}}{4}-\frac{y^{2}}{9}\end{array} \) Expand using the formula \(\begin{array}{l}a^{2}-b^{2}=(a-b)(a+b)\end{array} \) Consider a = 5/2x b =... View Article