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Find the equation of line through (−4,1,3) and parallel to the plane x + y + z = 3 while the line intersects another line whose equation is x + y – z = 0 = x + 2y -3z + 5

a) \(\begin{array}{l}\frac{x+4}{-3}= \frac{y-1}{-2}=\frac{z-3}{1}\end{array} \) b) \(\begin{array}{l}\frac{x+4}{1}= \frac{y-1}{2}=\frac{z-3}{1}\end{array} \) c) \(\begin{array}{l}\frac{x+4}{-3}= \frac{y-1}{2}=\frac{z-3}{1}\end{array} \) d) \(\begin{array}{l}\frac{x+4}{-1}= \frac{y-1}{2}=\frac{z-3}{-3}\end{array} \) Solution: Family of planes... View Article