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[latex]Fe{{C}_{2}}{{O}_{4}},F{{e}_{2}}{{({{C}_{2}}{{O}_{4}})}_{3}},FeS{{O}_{4}},F{{e}_{2}}{{(S{{O}_{4}})}_{3}}[/latex] one mole each, will react with how many moles of [latex]KMn{{O}_{4}}[/latex]

a.1 b.2 c.3 d.5 Answer: (b) \(\begin{array}{l}Fe{{C}_{2}}{{O}_{4}}+KMn{{O}_{4}} \end{array} \)→\(\begin{array}{l} {{}}F{{e}^{3+}}+C{{o}_{2}}+M{{n}^{2+}}\end{array} \) \(\begin{array}{l}F{{e}_{2}}{{\left( {{C}_{2}}{{O}_{4}} \right)}_{3}}+MnO_{4}^{-}\end{array} \) → \(\begin{array}{l}{{}}F{{e}^{3+}}\end{array} \) \(\begin{array}{l}F{{e}_{3}}{{O}_{4}}\end{array} \)... View Article

What will the order of magnetic moment (μ) be

Given complexes are low spin complexes, \(\begin{array}{l}{{[V{{(CN)}_{6}}]}^{4-}}\end{array} \) \(\begin{array}{l}{{[Cr{{(N{{H}_{3}})}_{6}}]}^{2+}}\end{array} \) \(\begin{array}{l}{{[Ru{{(N{{H}_{3}})}_{6}}]}^{3+}}\end{array} \) \(\begin{array}{l}{{[Fe{{(CN)}_{6}}]}^{4-}}\end{array} \) Then order of magnetic moment (μ)... View Article