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T square – 15. Find the zeros of the following quadratic polynomials

\(\begin{array}{l}t^{2}-15\end{array} \) \(\begin{array}{l}t^{2}-15 = 0\end{array} \) \(\begin{array}{l}(t+sqrt{15})(t-sqrt{15})=0\end{array} \) \(\begin{array}{l}(t+sqrt{15})=0 (t-sqrt{15})=0\end{array} \) \(\begin{array}{l}t=-sqrt{15}\end{array} \) and \(\begin{array}{l}t=sqrt{15}\end{array} \) t=−15 or t=15. Hence,... View Article

Find the value of x, if: 8^255=(32)^x

\(\begin{array}{l}(8)^{255}=(32)^{x}\end{array} \) \(\begin{array}{l}(2^{3})^{255}\end{array} \) = \(\begin{array}{l}(2^{5})^{x}\end{array} \) \(\begin{array}{l}2^{765}=2^{5x}\end{array} \) 5x=765 x=153

Factorise 6x^2+17x+5

\(\begin{array}{l}6x^{2}+17x+5\end{array} \) Factorise by splitting the middle term \(\begin{array}{l}6x^{2}+2x+15x+5\end{array} \) =2x(3x+1)+5(3x+1) =(3x+1)(2x+5)