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∫[(x2 + 1) √(x + 1)] dx =

1) \(\begin{array}{l}\frac{(x+1)^{7 / 2}}{7}-2 \frac{(x+1)^{5 / 2}}{5}+2 \frac{(x+1)^{3 / 2}}{3}+C\end{array} \) 2)\(\begin{array}{l}2\left[\frac{(x+1)^{7 / 2}}{7}-2 \frac{(x+1)^{5 / 2}}{5}+2 \frac{(x+1)^{3 / 2}}{3}\right]+C\end{array}... View Article

Cairn Tax Dispute

In December 2020, the Permanent Court of Arbitration (PCA) ruled against India in retrospective tax dispute between the Indian Government... View Article

Parliamentary Forums

Parliamentary Forums are established in order to provide a platform for interaction and discussion of critical issues with the ministers... View Article

∫[(4ex + 6e-x) / (9ex – 4e-x)] dx =

1) \(\begin{array}{l}\frac{3}{2} x+\frac{35}{35} \log \left|9 e^{2 x}-4\right|+C\end{array} \) 2) \(\begin{array}{l}\frac{3}{2} x+\frac{36}{36} \log \left|9 e^{2 x}-4\right|+C\end{array} \) 3) \(\begin{array}{l}-\frac{3}{2} x+\frac{35}{36} \log... View Article