∫{1 / (x + x5)} dx = f (x) + c, then the value of ∫(x4) / (x + x5) dx is
1) log x – f (x) + C 2) f (x) + log x + C 3) f (x) –... View Article
1) log x – f (x) + C 2) f (x) + log x + C 3) f (x) –... View Article
1) k = – 1 / 2 2) k = – 1 / 8 3) k = – 1 /... View Article
1) tan x / 2 2) log |tan (x / 2)| 3) log |sin x| 4) log |cos x| Solution:... View Article
1) 0 2) x + C 3) (x / 2) – (cos πx / 2π) + c 4) [1 /... View Article
1) 8 2) 12 3) 16 4) 2 5) 10 Solution: (5) 10 f’ (x) ≥ 2 f (x) ≥ 2x... View Article
1) x2 + log x + c 2) x2 / 2 + log x + c 3) x / 2... View Article
1) 2 √(x2 + 1) + sin-1 x + c 2) √(x2 – 1) + sin-1 x + c 3)... View Article
1) x / [(log x)2 + 1] + c 2) [xex / (1 + x2)] + c 3) [x /... View Article
1) cot (ax / 2) + c 2) (1 / a) tan (ax / 2) + c 3) (1 /... View Article
1) 2 log (ex + 1) 2) 2 log |e2x – 1| 3) 2 log |ex + 1| – x... View Article
1) (1 / √2) log |tan [(x / 2) – (π / 8)]| + c 2) (1 / √2) log... View Article
1) tan-1 x + c 2) etan^(-1)x + 2x + c 3) etan^(-1)x + c 4) etan^(-1)x-x + c 5)... View Article
1) (1 / (7 loge 4) (4-x)) – (4 / (loge 7) (7-x) + c 2) (1 / (7 loge... View Article
1) x + c 2) (3 / 2) sin 2x + c 3) (- 3 / 2) cos 2x +... View Article
1) log [(x – 1) / (x + 1)] + c 2) log |(x + 1) / (x – 1)|... View Article
1) log (x2 + 4x + 3) + c 2) (1 / 3) tan-1 [(x + 2) / 3] +... View Article
1) (1 / 2) log |(x / 2) + (π / 12)| + c 2) (1 / 2) log [(x... View Article
1) Statement I is correct, Statement II is correct; Statement II is the correct explanation for Statement I 2) Statement... View Article
1) tan-1 (x + 1) 2) 2 tan-1 (x + 1) 3) – tan-1 (x + 1) 4) 3 tan-1... View Article
1) (- 1 / (x + 1)) + c 2) (1 / 5) log (x + 1) + c 3)... View Article