If x2/a + y2/b + 2xy/h = 0 represents a pair of straight lines and slope of one line is twice the other, then ab : h2 is
1) 9 : 8 2) 8 : 9 3) 1 : 2 4) 2 : 1 Solution: Given x2/a +... View Article
1) 9 : 8 2) 8 : 9 3) 1 : 2 4) 2 : 1 Solution: Given x2/a +... View Article
1) bm2 + 2hm + a = 0 2) bm2 + 2hm – a = 0 3) am2 + 2hm... View Article
1) h2 = 2ab 2) h2 > 2ab 3) \(\begin{array}{l}\begin{vmatrix} a &h &g \\ h & b& f\\ g& f... View Article
1) x2 – xy – y2 = 1 2) –x2 + xy – y2 = 1 3) 4x2 – 4xy... View Article
1) 6x2 + 5xy + y2 = 0 2) 6y2+ 5xy + x2 = 0 3) 6x2 – 5xy +... View Article
1) Real and coincident 2) Real and different 3) Imaginary and different 4) None of the above Solution: Given 4x2... View Article
1) ax – by = 0, bx + ay = 0 2) ax – by = 0, bx – ay... View Article
1) x + 4y = 0 and x + 3y = 0 2) 2x – 3y = 0 and x... View Article
1) (a – b)2 = h2 2) (a + b)2 = h2 3) (a – b)2 = 4h2 4) (a... View Article
1) y = x 2) y = –x 3) y = mx 4) my = x Solution: Given equation of... View Article
1) a 2) b 3) h 4) Any real number Solution: Given angle bisectors are coincident. This means the angle... View Article
1) h(1 + m2) + m (a – b) = 0 2) h(1 – m2) + m (a + b)... View Article
1) 8x2 + 11xy – 8y2 = 0 2) 8x2 – 11xy – 8y2 = 0 3) 16x2 + 11xy... View Article
1) c2 – 4 = 0 2) c2 – 8 = 0 3) c2 – 9 = 0 4) c2... View Article
1) 1/√3 2) 2/5 3) ±3√5 4) None of these Solution: Given (x – 2y)2 + k(x – 2y) =... View Article
1) (xy1 – yx1)2 = d2(x2 + y2) 2) (x1y1 – xy)2 = (x2 + y2) 3) (xy1 + x1y)2... View Article
1) x2 + y2 = (y – x)2 2) x2 + y2 + (y – x)2 = 0 3) x2... View Article
1) {–2, 2} 2) {–3, 3} 3) {–4, 4} 4) {–5, 5} Solution: Given curve is x2 + y2 =... View Article
1) x2 – y2 = 0 2) xy = 0 3) xy – x2 = 0 4) y2 + xy... View Article
1) 1/2 2) 5/√2 3) √10 4) √(5/2) Solution: Given x2 – 6xy + 9y2 + 3x – 9y –... View Article