If y = t4/3-3t-2/3, then dy/dt =
(1) (2t2 + 3)/3t5/3 (2) (2t2 + 3)/t5/3 (3) 2(2t2 + 3)/t5/3 (4) 2(2t2 + 3)/3t5/3 Solution: Given y =... View Article
(1) (2t2 + 3)/3t5/3 (2) (2t2 + 3)/t5/3 (3) 2(2t2 + 3)/t5/3 (4) 2(2t2 + 3)/3t5/3 Solution: Given y =... View Article
(1) 3/√(1- x2) (2) -1/√(1- x2) (3) 1 (4) none of these Solution: Let y = sin-1 (3x – 4x3)... View Article
(1) 0 (2) 1/(√x + 1) (3) 1 (4) none of these Solution: Given y = sec-1((√x + 1)/(√x –... View Article
(1) 1/√x(1+4x) (2) 2/√x(1+4x) (3) 4/√x(1+4x) (4) none of these Solution: Let y = tan-1 4√x/(1-4x) We know tan 2A... View Article
(1) -cos [cos (sin x)] sin (cos x) cos x (2) -cos [cos (sin x)] sin (sin x) cos x... View Article
(1) (φ’ψ’’- ψ’φ’’)/(φ’)2 (2) (φ’ψ’’- ψ’φ’’)/(φ’)3 (3) φ’’/ψ’’ (4) ψ’’/φ’’ Solution: Given x = φ(t) and y = ψ(t). dx/dt... View Article
1) 0 2) 12 3) 16 4) 32 Correct option: (2) 12 Solution: Equation of the given curve is: y... View Article
1) P(–1) is not minimum and P(1) is the maximum of P 2) P(–1) is not minimum but P(1) is... View Article
1) c2 / √ab 2) c3 / ab 3) c3 / √2ab 4) c3 / 2ab Solution: (3) c3 /... View Article
1) (5 / 3, 0) 2) (1 / 3, 0) 3) (3, 0) 4) (1, 0) Solution: (1) (5 /... View Article
1) b 2) √a 3) √b 4) √b / a Solution: (4) √b / a f (x) = ax +... View Article
1) A minimum but no maximum 2) A maximum but no minimum 3) Neither maximum nor minimum 4) Both maximum... View Article
1) More than one minimum 2) Exactly one minimum 3) At least one maximum 4) None of the above Solution:... View Article
1) 2 / 3 2) 3 / 4 3) 1 / 3 4) 1 / 4 Solution: (1) 2 /... View Article
1) 1 / 2 2) 1 / √3 3) 1 / √2 4) None of these Solution: (2) 1 /... View Article
1) – 1 / 4 2) – 1 / 8 3) 1 / 2 4) 1 / 16 Solution: (2)... View Article
1) –2 2) 2 3) 1 4) –1 Solution: (3) 1 f (x) = x + (1 / x) f’... View Article
1) 1 / 2 2) 3 / 4 3) 1 4) 4 / 3 Solution: (1) 1 / 2 f... View Article
1) The cubic has minima at – √p / 3 and maxima at √p / 3 2) The cubic has... View Article
1) √ab 2) a / b 3) 2ab 4) ab Solution: (3) 2ab Area of rectangle ABCD = (2a cos... View Article