Latest Posts

If Cot Theta Plus Cot Pi 4 Plus Theta 2 Then

1) 2nπ ± π/6 2) 2nπ ± π/3 3) nπ ± π/3 4) nπ ± π/6 Answer: (4) nπ ±... View Article

1) k > 3 2) k < 2 3) k > 3 4) 2 ≤ k ≤ 6 Answer: (4)... View Article

1) nπ + π/4, nπ + π/3 2) nπ – π/4, nπ + π/3 3) nπ + π/4, nπ –... View Article

1) nπ ± π/3 2) nπ ± π/6 3) 2nπ ± π/3 4) 2nπ ± π/6 Answer: (3) 2nπ ±... View Article

1) nπ ± π/3 2) 2nπ ± π/6 3) nπ ± π/6 4) 2nπ ± π/3 Answer: (4) 2nπ ±... View Article

1) nπ ± π/6 2) nπ + π/6 3) 2nπ ± π/6 4) None of these Answer: (1) nπ ±... View Article

1) nπ/4, nπ/4 + π/18 2) nπ/3, nπ/3 + (-1)n π/18 3) nπ/4, nπ/3 + (-1)n π/18 4) nπ/6, nπ/3... View Article

(1) tan-1 5/(1+anan-1) (2) tan-1 5a1/(1+ana1) (3) tan-1 (5n-5)/(1+ana1) (4) none of these Solution: Given a1, a2, a3 …an are... View Article

(1) 0 (2) 1 (3) 2 (4) None of these Solution: Given a,b,c,d are distinct integers in AP such that... View Article

(1) 1/(b-a) + 1/(b-c) = 1/b (2) ac/(a+c) = b (3) (b+a)/(b-a) + (b+c)/(b-c) = 1 (4) None of these... View Article

(1) (n-2) + 1/(n-2) (2) 1/(n-2) (3) n-2 (4) n+2 Solution: Given a1, a2, a3 …an are in AP a1... View Article

(1) 10 (2) 20 (3) 30 (4) 40 Solution: Given S1, S2,….. S101 are in AP. Let d be the... View Article

(1) p,q,r are in AP (2) p2,q2,r2 are in AP (3) 1/p,1/q,1/r are in AP (4) None of these Solution:... View Article

(1) n(a12 -a2n2)/(2n-1) (2) 2n(a2n2 -a12)/(n-1) (3) n(a12 +a2n2)/(n+1) (4) none of these Solution: Given a1, a2,a3…a2n form an AP.... View Article

(1) (n-1)/a1an (2) 1/a1an (3) (n+1)/a1an (4) n/a1an Solution: Given a1, a2,…an are in AP. Let d be the common... View Article

(1) 7/72, 5/36 (2) 17/72, 5/36 (3) 7/36, 5/72 (4) 5/72, 17/72 Solution: Given A1 and A2 are 2 AM’s... View Article

(1) (r(r+1)/2x) + ry (2) r(r-1)/2x (3) (r(r-1)/2x) – ry (4) (r(r+1)/2y) + rx Solution: Given nth term, an =... View Article

(1) (n/2) log (an/bn) (2) (n/2) log (an+1/bn) (3) (n/2) log (an+1/bn-1) (4) (n/2) log (an+1/bn+1) Solution: ∑r=1n log (ar/br-1)... View Article

(1) sec a1 – sec an (2) cot a1 – cot an (3) tan a1 – tan an (4) cosec... View Article

(1) ab/(b-a) (2) ab/2(b-a) (3) 3ab/2(b-a) (4) 3ab/4(b-a) Solution: Let d be the common difference of an AP. Given first... View Article