Find A B And C Between 2 And 18 Such That A B C 25 2 A B Are In Ap And B C 18 Are In Gp
(1) 5, 8, 12 (2) 4, 8, 13 (3) 3, 9, 13 (4) 5, 9, 11 Solution: Given a +... View Article
(1) 5, 8, 12 (2) 4, 8, 13 (3) 3, 9, 13 (4) 5, 9, 11 Solution: Given a +... View Article
(1) –150 (2) 150 times its 50th terms (3) 150 (4) Zero Solution: Let a be the first term and... View Article
(1) S1 – S2 (2) S2 – S1 (3) (S1 – S2)/2 (4) None of these Solution: Let d be... View Article
(1) 21,17,13 (2) 20,16,12 (3) 22,18,14 (4) 24,20,16 Solution: Let a-d, a, a+d are the three numbers. Sum = 3a... View Article
(1) 4,5,6 (2) 3,5,7 (3) 1,5,9 (4) 2,5,8 Solution: Let a-d, a, a+d are the three numbers. Then sum =... View Article
(1) 10 (2) 8 (3) 9 (4) None of these Solution: Given first term, a = 2 Last term, b... View Article
(1) n(a+b)/2 (2) n(a+b) (3) (n+1)(a+b)/2 (4) (n+1)(a+b) Solution: Let A1, A2, …An be the arithmetic means between a and... View Article
(1) (n-1)/2 (2) (n+1)/2 (3) n/2 (4) n Solution: We know sum of first n natural numbers, (1+2+3+…n) = n(n+1)/2... View Article
(1) 1/4, 4/1 (2) 3/4, 4/3 (3) 2/5, 5/2 (4) 3/2, 2/3 Solution: Let x be the number. Then the... View Article
(1) 1 (2) -1 (3) 0 (4) none of these Solution: Arithmetic mean of a and b, AM = (a+b)/2... View Article
(1) 35 (2) 36 (3) 37 (4) 40 Solution: Given (3+5+7+… n tems)/(5+8+11+…10 terms) = 7 Consider (3+5+7+… n tems)... View Article
(1) 10 (2) 11 (3) 12 (4) None of these Solution: Let a, a+d, a+2d, a+3d are the terms in... View Article
(1) (P + 1)2 (2) (p + 1)3 (3) (2p + 1)(p + 1)2 (4) p3 + (p + 1)3... View Article
(1) 4 (2) 6 (3) 8 (4) 10 Solution: Let a be the first term and d be the common... View Article
(1) P+Q (2) 2Q (3) Q (4) 2P+3Q Solution: Let a be the first term and d be the common... View Article
(1) 2a – d = 0 (2) a – d = 0 (3) a – 2d = 0 (4) None... View Article
The solution of \(\begin{array}{l}\log _{\sqrt{3}}x+ \log _{\sqrt[4]{3}}x+\log _{\sqrt[6]{3}}x+ …\log _{\sqrt[16]{3}}x=36\end{array} \) (1) x = 3 (2) x = 4√3 (3)... View Article
1) 2Sn 2) S3n 3) S3n/3 4) Sn/2 Solution: The sum of n terms of an arithmetic progression, Sn =... View Article
(1) (m-1)/(n-1) (2) (n-1)/(m-1) (3) (2m-1)/(2n-1) (4) (2n-1)/(2m-1) Solution: Given Sm/Sn = m2/n2 Sm = (m/2)(2a+(m-1)d) Sn = (n/2)(2a+(n-1)d) Sm/Sn... View Article
1) n(n – 1) 2) n(n-1)/2 3) n(n + 1) 4) n(n+1)/2 Solution: The sum of the first n natural... View Article