1) 1/n [1-(1-p)n] 2) [1-(1-p)n] 3) [1/(n-1)] [1-(1-p)n] 4) None of these Solution: Option (1)1/n [1-(1-p)n] Given that, p be... View Article
1) ⅛ 2) 13/15 3) 1/7 4) None of these Solution: Option (4) None of these It is given that... View Article
1) (3p+2p2)/2 2) (p+3p2)/4 3) (p+3p2)/2 4) (3p+2p2)/4 Solution: Option (1) (3p+2p2)/2 P (exactly one of the events A or... View Article
1) p=1, q=0 2) p=⅔, q= 1/2 3) There are infinitely many values of p and q 4) All of... View Article
1) 2/3 2) 1/2 3) 3/4 4) ⅓ Solution: Option (3) ¾ The required probability = P(sum is odd) +... View Article
1) 1/5 2) 2/5 3) 4/5 4) None of these Solution: Option (2) ⅖ Let A be the event that... View Article
1) 2:(n-3) 2) (n-3):2 3) (n-2):2 4) 2: (n-2) Solution: Option (2) (n-3):2 The number of ways, in which “n”... View Article
1) 3/5 2) 18/5 3) 1/5 4) 6/5 Solution: Option (3) 1/5 Total cases = 5! The number is divisible... View Article
1) 16/21 2) 8/21 3) 32/12 4) None of these Solution: Option (1) 16/21 Total number of cases = 64C3... View Article
1) 10/133 2) 9/133 3) 9/1330 4) None of these Solution: Option (1) 10/133 Total Ways = 21C3 If the... View Article
1) [(k-1)(k-2)]/432 2) [k(k-1)]/432 3) k2/432 4) None of these Solution: Option (1) [(k-1)(k-2)]/432 If three dice are, the total... View Article
1) (¾)50 2) (2/7)50 3) (⅛)50 4) (⅞)50 Solution: Option (1) (¾)50 For each toss, there will be 4 choices.... View Article
1) 3/4 2) 1/2 3) 1/3 4) None of these Solution: Option (1) ¾ The probability of getting head, p... View Article
1) 1/9 2) 2/7 3) 1/18 4) None of these Solution: Option (3) 1/18 Out of 64 squares, two squares... View Article
1) (9/10)6 2) (8/15)7 3) (⅗)7 4) None of these Solution: Option (3) (⅗)7 Total outcomes = 157 Favourable outcomes... View Article
1) (n+2)/(2n+1) 2) (n+2)/(2(n+1)) 3) n/(n+1) 4) 1/(n+1) Solution: Option (2) (n+2)/(2(n+1)) P(E) = P(u2) + P(u4) + …+P(un) =... View Article
1) 125/216 2) 25/216 3) 5/36 4) 25/36 Solution: Option (4) 25/36. P[(X ≥ 6)/X>3] = [P[(X>3)/(X ≥ 6)].P(X ≥... View Article
1) 125/216 2) 25/36 3) 5/36 4) 25/216 Solution: Option (2) 25/36 P(X ≥ 3) = 1- [P(X=1) + P(x=... View Article
1) 25/216 2) 25/36 3) 5/36 4) 125/216 Solution: Option (1) 25/216 P(X= 3) = (⅚)(⅚)(⅙) P(X= 3) = 25/216.
1) 17/23 2) 11/23 3) 15/23 4) 12/23 Solution: Option (4) 12/23 P(H) = ½, P(T) = ½, Let W... View Article