Are Double Displacement Reactions Redox
At the same time, reduction and oxidation occur, so the reactions are called redox reactions . The loss of electrons... View Article
Latest Posts
What Are The Properties Of Plaster Of Paris
The Paris Plaster is non-combustible and non-flammable. It normally has low chemical reactivity but, under extreme conditions, can act as... View Article
If The First And 2n 1 Th Term Of A Ap Gp And Hp Are Equal And Their Nth Terms Are A B C Respectively Then
(1) a = b = c (2) a ≥ b ≥ c (3) a + c = b (4) ac... View Article
If A B C Are In Ap Then The Straight Line Ax By C Eq 0 Will Always Pass Through The Point
(1) (-1, -2) (2) (1, -2) (3) (-1, 2) (4) (1, 2) Solution: Given a, b, c are in AP.... View Article
If X1 X2 X3 As Well As Y1 Y2 Y3 Are In Gp With The Same Common Ratio Then The Points X1 Y1 X2 Y2 And X3 Y3
(1) lie on a straight line (2) lie on a circle (3) lie on an ellipse (4) are vertices of... View Article
The Sum To Infinity Of The Following Series 2 Pls 1 By 2 Plus 1 By 3 Plus 1 By 2 Sq 1 By 3 Sq Will Be
(1) 3 (2) 4 (3) 7/2 (4) 9/2 Solution: Let S = 2 + 1/2 + 1/3 + 1/22 +... View Article
If Between 1 And 1 By 31 There Are N Hms And Ratio Of 7th And N 1 Th Harmonic Means Is 9 5 Then Value Of N Is
(1) 12 (2) 13 (3) 14 (4) 15 Solution: Given n HMs between 1 and 1/31. So common difference, d... View Article
For All Positive Integral Values Of N The Value Of 3 1 2 Plus 3 2 3 Plus 3 3 4 Plus 3 N N Plus 1 Is
(1) n(n+1)(n+2) (2) n(n+1)(2n+1) (3) (n-1)n(n+1) (4) (n-1)n(n+1)/2 Solution: S = 3.1.2+3.2.3+3.3.4+…+3.n.n+1 Here tr = 3r(r+1) = 3r2+3r S =... View Article
The Sum Of The Series 1 By 3 Into 7 Plus 1 By 7 Into 11 Is
(1) 1/3 (2) 1/6 (3) 1/9 (4) 1/12 Solution: Let S = 1/3×7 + 1/7×11 + 1/11×15+… = (¼)(⅓ –... View Article
The Sixth Hm Between 3 And 6 By 13 Is
(1) 63/120 (2) 63/12 (3) 126/105 (4) 120/63 Solution: For HP, xn = (n+1)ab/(na+b) x6 = (7×3×6/13)/(6×3+6/13) = 126/240 =... View Article
The Fifth Term Of The Hp 2 2 And 1 By 2 3 And 1 By 3 Will Be
(1) \(\begin{array}{l}5\frac{1}{5}\end{array} \) (2) \(\begin{array}{l}3\frac{1}{5}\end{array} \) (3) 1/10 (4) 10 Solution: 2, 2 ½ , 3 ⅓ are in HP.... View Article
Which Number Should Be Added To The Numbers 13 15 19 So That The Resulting Numbers Be The Consecutive Terms Of A Hp
(1) 7 (2) 6 (3) –6 (4) –7 Solution: Let x be the number added to 13, 15 and 19... View Article
If A1 A2 A10 Be In Ap H1 H2 H10 Be In Hp A1 Equal H1 Eq 2 A10 Equal H10 Eq 3 Then A4h7 Equals
(1) 2 (2) 3 (3) 5 (4) 6 Solution: Given a1, a2, …a10 be in AP. a1 = h1 =... View Article
The Sum Of Three Consecutive Terms In A Geometric Progression Is 14 If 1 Is Added To The First And The Second Terms And 1 Is Subtracted From The Third
(1) 1 (2) 2 (3) 4 (4) 8 Solution: Let a, ar, ar2 be the three consecutive terms in GP.... View Article
150 Workers Were Engaged To Finish A Piece Of Work In A Certain Number Of Days 4 Workers Dropped
(1) 15 (2) 20 (3) 25 (4) 30 Solution: Let the number of days in which 150 workers finish the... View Article
If The Ratio Of Hm And Gm Between Two Numbers A And B A Greater Than B Is 4 5 Then The Ratio Of The Two Numbers Will Be
(1) 1 : 2 (2) 2 : 1 (3) 4 : 1 (4) 1 : 4 Solution: HM of a... View Article
Sum Of N Terms Of Series 12 16 24 40 Will Be
(1) 2(2n-1)+8n (2) 2(2n-1)+6n (3) 3(2n-1)+8n (4) 4(2n-1)+8n Solution: Let S = 12 + 16 + 24 + 40 +…tn... View Article
If Three Positive Real Numbers A B C Are In Ap And If Abc Eq 64 Then The Minimum Value Of B Is
(1) 6 (2) 5 (3) 4 (4) 3 Solution: We know AM ≥ GM (a+b+c)/3 ≥ (abc)1/3 …(i) Since a,... View Article
If An Ap A Eq 1 Sn S2n Sn Eq Constant For All N Then The Common Difference D
(1) 4 (2) 1/2 (3) 2 (4) 3 Solution: Given a = 1 S1/(S2-S1) = S2/(S4-S2) S1(S4-S2) = S2(S2-S1) S1S4-S1S2... View Article
The Nth Term Of An Ap Is P2 And The Sum Of The First N Terms Is S2 The First Term Is
(1) (p2n+2s2)/n (2) (2s2+p2n)/n2 (3) (ps2-p2s)/n (4) (2s2-p2n)/n Solution: The nth term of AP, tn = a+(n-1)d = p2 Sum... View Article
