How Do You Simplify 1 I 2
(1+i)2 We can simplify using the identity (a + b)2 = a2 + 2ab + b2 (1+i)2= 1 + 2i... View Article
(1+i)2 We can simplify using the identity (a + b)2 = a2 + 2ab + b2 (1+i)2= 1 + 2i... View Article
The integers which can be generated by multiplying the two smallest positive integers and contain at least one divisor other... View Article
Express sin x/2 in terms of cos x using the double angle identity Solution From the trigonometric identity we know... View Article
\(\begin{array}{l}\sqrt{3}/2\end{array} \) We know that √3= 1.732 Hence \(\begin{array}{l}\sqrt{3}/2\end{array} \)= 1.732/2=0.866
We can find the square root of 0.9 by the following method 0.9 can be expressed as 9/10 √0.9=\(\begin{array}{l}\sqrt{\frac{9}{10}}\end{array} \)... View Article
UPSC Current Affairs Preparation: The Hindu Analysis Watch expert analysis of ‘The Hindu’ dated 05th January 2021. Important news and... View Article
CNA 05 Jan 2021:- Download PDF Here TABLE OF CONTENTS A. GS 1 Related B. GS 2 Related HEALTH 1.... View Article
January 4th, 2021, PIB:- Download PDF Here TABLE OF CONTENTS 1. Indian scientific expedition to Antarctica 2. CSIR-NPL 3. TRIFOOD... View Article
1) an equilateral triangle 2) an isosceles triangle 3) a right angled triangle 4) collinear Answer: (3) A right angled... View Article
1) 2 2) 4 3) 6 4) 8 Answer: (1) 2 Solution: Given, 3i+6j+9k,i+2j+3k,2i+3j+k and 4i+6j+λk are coplanar Let, OA... View Article
1) 12 2) 2 3) 0 4) –12 Answer: (4) -12 Solution: Given, (a.j)×(2j−3k) We can write, a.(j×(2j−3k)) =a.(−3(j×k)) =-(a,i)... View Article
1) 8 α. (a + b + c) 2) α . (a + b + c) 3) 8(a + b... View Article
1) 27 2) 9 3) 81 4) 48 Answer: (3) 81 Solution: ⅙ [αβγ] = 27 Volume = ⅙ [(a+2b−c)x... View Article
1) 5 cu units 2) 10 cu units 3) 15 cu units 4) 20 cu units Answer: (2) 10 cu... View Article
1) λ=4 2) λ=-4 3) λ=-7 4) λ=7 Answer: (2) λ=-4 Solution: Vectors a,b, and c are coplanars Then |abc|... View Article
1) a = 3, b = 1 2) a = 9, b = 1 3) a = 3, b =... View Article
1) 10√3 2) 5√3 3) 8 4) 4 Answer: (2) 5√3 Solution: Here a=3i+j−2k,b=i−3j+4k \(\begin{array}{l}\mathbf{a} \times \mathbf{b}=\left|\begin{array}{ccc} \mathrm{i} & \mathrm{j}... View Article
1) 6 2) 5 3) 4 4) 3 Answer: (2) 5 Solution: |a+b| = 5 |a+b|2 = 25 Using (a+b)2... View Article
1) 6i – 7j + k 2) -2i+6j-10k 3) -4i-2j-5k 4) None of the above Answer: (1) 6i – 7j... View Article
1) π/6 2) π/3 3) π/2 4) π/4 Answer: (2) π/3 Solution: Given, ∣A × B∣= √3 ∣A.B∣ AB sinθ=√3ABcosθ... View Article