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If The Am Of A And B Then A Power N Plus 1 B Power N Plus 1 By An Plus Bn Then N Equal

(1) 2 (2) 3 (3) 1 (4) 0 Solution: AM of a and b = (a+b)/2 Given AM = (an+bn)/(an-1... View Article

Tan Inverse 1 By 3 Plus Tan Inverse 1 By 7 Plus Tan Inverse 1 By 13 Plus Tan Inverse 1 By 9703 Equal

(1) π/4 (2) π/6 (3) π/3 (4) tan-1(0.98) Solution: tan-1(1/3) = tan-1(2-1)/1+(2×1) = tan-12 – tan-11 tan-1(1/7) = tan-1(3-2)/1+(3×2) =... View Article

1 Plus 3 Plus 7 Plus 15 Plus 10 Terms Equal

(1) 2012 (2) 2046 (3) 2038 (4) 2036 Solution: Let Sn = 1 + 3 + 7 + 15 +... View Article

1 By 2 Into 5 Plus 1 By 5 Into 8 Plus 100 Terms

(1) 25/160 (2) 1/6 (3) 25/151 (4) 25/152 Solution: Let S = (1/2×5) + (1/5×8) + (1/8×11) + …100 terms... View Article

1 Cube By 1 Plus 1 Cube Plus 2 Cube By 1 Plus 2 Plus Upto 15 Terms Equal

(1) 446 (2) 680 (3) 600 (4) 540 Solution: 13/1 + (13+23)/(1+2) + (13+23+33)/(1+2+3) +….15 terms = Here tn =... View Article

1 Cube By 1 Plus 1 Cube Plus 2 Cube By 2 Plus Upto N Terms Equal

(1) n(n+1)(n+2)(5n+3)/48 (2) n(n+1)(n+2)(n+3)/24 (3) n(n+1)(n+2)(7n+1)/48 (4) n(n+1)(n+2)(3n+5)/48 Solution: 13/1 + (13+23)/2 + (13+23+33)/3 +….upto n terms = Here tn... View Article

3 By 4 Plus 5 By 36 Plus 7 By 144 Plus 9 By 400 Infinite Terms Equal

(1) 0.8 (2) 0.9 (3) 1 (4) 0.99 Solution: 3/4 + 5/36 + 7/144 + 9/400 + …infinite terms =... View Article

2 Plus 12 Plus 36 Plus 80 N Terms Equal

(1) n(n+1)(n+2)(3n+5)/24 (2) n(n+1)(n+2)(3n+1)/12 (3) n(n+1)(n+2)(n+5)/24 (4) n(n+1)(n+2)(n+3)/12 Solution: 2 + 12 + 36 + 80 + … n terms... View Article

4 Plus 18 Plus 48 N Terms Equal

(1) n(n+1)(n+2)(3n+5)/12 (2) n(n+1)(n+2)(5n+3)/12 (3) n(n+1)(n+2)(7n+1)/12 (4) n(n+1)(n+2)(9n-1)/12 Solution: 4 + 18 + 48 + … n terms = ∑n(n+1)2... View Article

1 Plus 3 Plus 7 Plus 13 100 Terms Eq

(1) 1010000/2 (2) 1000200/3 (3) 1015050/3 (4) 1051050/3 Solution: Let Sn = 1 + 3 + 7 + 13 +... View Article

If S1 S2 S3 Sn Are The Sums Of Infinite Gps Whose First Terms Ars 1 2 3 N And Whose Common Ratios Are

(1) n(n+3)/2 (2) n(n+4)/2 (3) n(n-3)/2 (4) n(n+1)/2 Solution: ∑i = 1nSi = ∑i = 1na/(1-r) S1 = 1/(1-½) =... View Article

If M Plus 1 Th N Plus 1th And R Plus 1 Th Terms Of An Ap Are In Gp And M N R Are In Hp Then The Common Difference Of The Ap Is

(1) -a/n (2) -n/2a (3) 2a/n (4) -2a/n Solution: Given m, n, r are in HP. So 2/n = (r+m)/mr... View Article

Am Of The Three Numbers Which Are In Gp Is 14 By 3 If Adding 1

(1) 91 (2) 80 (3) 84 (4) 88 Solution: Let a, ar, ar2 be the numbers in GP. Given AM... View Article

If The Harmonic Mean And Geometric Mean Of Two Numbers A And B Are 4 And 3 Root 2 Respectively Then The Interval A B Equal

(1) [3, 6] (2) [2, 7] (3) [4, 5] (4) [1, 8] Solution: Given HM = 4 2ab/(a+b) = 4... View Article

If A1 A2 A3 A4 A5 Are In Ap With Common Difference Not Equal 0 Then Find The Value Sigma I Equal 1 To 5ai When A3 Equal 2

(1) 10 (2) 5 (3) 20 (4) None of these Solution: a3 = 2 a+2d = 2 So a =... View Article

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