A Pack Of Cards Contains 4 Aces 4 Kings 4 Queens And 4 Jacks Two Cards Are Drawn At Random The Probability That At Least One Of These
1) 9/20 2) 3/16 3) 1/6 4) 1/9 Solution: Option (1) 9/20 Total cases = 16C2 The probability that at... View Article
1) 9/20 2) 3/16 3) 1/6 4) 1/9 Solution: Option (1) 9/20 Total cases = 16C2 The probability that at... View Article
1) 3/5525 2) 2/5525 3) 1/5525 4) None of these Solution: Option (3) 1/5525 Total cases = 52C3 = 22100... View Article
1) 1/3 2) 1/2 3) 1/4 4) None of these Solution: Option (2) ½ Total cases = 25C2 = 300... View Article
1) 14/15 2) 11/15 3) 7/15 4) 4/15 Solution: Option (3) 7/15 Total cases = 15C2 = 105 Favourable cases... View Article
1) 21/316 2) 19/316 3) 1/4 4) None of these Solution: Option (2) 19/316. Total cases = 80C2 Favourable cases... View Article
1) 1/15 2) 14/15 3) 1/5 4) 4/5 Solution: Option (4) 4/5 Given that, S = {1, 2,3, 4, 5,... View Article
1) 2/19 2) 3/29 3) 17/19 4) 4/19 Solution: Option (3) 17/19 Total cases = 20C3 From the first 20... View Article
1) 14/29 2) 16/29 3) 15/29 4) 10/29 Solution: Option (3) 15/29 Total cases = 30C2 = 435 The sum... View Article
1) 1/3 2) 1/4 3) 5/12 4) 2/3 Solution: Option (4) ⅔ Total cases = 12C1 = 12 Favourable cases... View Article
1) (8C6 . 7C5)/15C11 2) (8C6 + 7C5)/15C11 3) 15/28 4) None of these Solution: Option (1) (8C6 . 7C5)/15C11... View Article
1) 2/801 2) 2/623 3) 1/267 4) 1/623 Solution: Option (1) 2/801 Total cases = 90C5 Favourable cases = 88C3... View Article
1) 1/34 2) 1/35 3) 1/17 4) 1/68 Solution: Option (2) 1/35 Total cases = 7! Ways Favourable cases =... View Article
1) 38C3 2) 37C2 3) 37C2/38C3 4) 666/8436 Solution: Option (3) 37C2/38C3 Total cases = 38C3 Favourable cases = 37C2... View Article
1) 4/5 2) 3/5 3) 2/5 4) 1/5 Solution: Option (1) 4/5 Total number of ways = 10! ways. Two... View Article
1) 1/8 2) 2/21 3) 1/32 4) 1/35 Solution: Option (4) 1/35 In an octagon, there are 8 vertices. Out... View Article
1) 3/11 2) 2/11 3) 8/11 4) None of these Solution: Option (1) 3/11 Total cases = 12C3 Favourable cases... View Article
1) 2/7 2) 3/7 3) 4/7 4) None of these Solution: Option (1) 2/7 Total cases = 7P5, where P... View Article
1) 0.55 2) 0.44 3) 0.22 4) 0.33 Solution: Option (1) 0.55 Total cases = 100C2 Favourable cases = 33C1.67C1... View Article
1) 1/729 2) 1/24 3) 1/21 4) 2/7 Solution: Option (4) 2/7 Total cases = 9C3 Favourable cases = 2C1... View Article
1) 1/17 2) 3/19 3) 2/19 4) 2/17 Solution: Option (4) 2/17 Total number of cards = 52 Total cases... View Article