If The Roots Of A B C X2 Plus Bc Ax Plus Ca B Eq 0 Be Equal Then A B C Are In
(1) A.P (2) G.P (3) H.P (4) None of these Solution: Given roots of the equation a(b – c)x2 +... View Article
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If A B C Are In Ap Then A By Bc 1 By C 1 By B Are In
(1) AP (2) GP (3) HP (4) None of these Solution: Since a, b, c are in AP, 2b =... View Article
If The Arithmetic Geometric And Harmonic Means Between Two Positive Real Numbers Be A G And H Then
(1) A2 = GH (2) H2 = AG (3) G = AH (4) G2 = AH Solution: Let a, b... View Article
If In An Infinite Gp First Term Is Equal To The Twice Of The Sum Of The Remaining Terms Then Common Ratio Is
(1) 1 (2) 2 (3) 1/3 (4) -1/3 Solution: Let a, ar, ar2….∞ be the series. Sum of remaining terms... View Article
Sum Of Infinite Number Of Terms In Gp Is 29 And Sum Of Their Square Is 100 The Common Ratio Of Gp Is
(1) 5 (2) 3/5 (3) 8/5 (4) 1/5 Solution: Let a, ar, ar2….∞ be the series. Given the sum of... View Article
0 5737373 Equals
(1) 284/497 (2) 284/495 (3) 568/990 (4) 567/990 Solution: Let x = 0.5737373… = 0.5+ (73/103) + (73/105) + …... View Article
The Value Of 4 1 By 3 4 1 By 9 4 1 By 27 Infinity Is
(1) 2 (2) 3 (3) 4 (4) 9 Solution: 41/3 41/9 41/27 ….. ∞ = 4(1/3 + 1/9 + 1/27... View Article
The value of [latex]a^{\log _{b}x}[/latex] where a = 0.2, b = √5, x = 1/4 + 1/8 + 1/16 + ….∞ is
(1) 1 (2) 2 (3) 1/2 (4) 4 Solution: Given x = 1/4 + 1/8 + 1/16 + ….∞ Here... View Article
The Sum Of The Series 5 05 Plus 1 212 Plus 0 29088 Plus Infinity Is
(1) 6.93378 (2) 6.87342 (3) 6.74384 (4) 6.64474 Solution: Given series is 5.05 + 1.212 + 0.29088 + … ∞... View Article
The Geometric Mean Of 1 2 2 Power 2 2n Is
(1) 2n/2 (2) n(n+1)/2 (3) 2n(n+1)/2 (4) 2(n – 1)/2 Solution: 1, 2, 22,….. 2n Here the number of terms... View Article
Bar 423 Equals
\(\begin{array}{l}0.\overline{423}\end{array} \) equals (1) 419/990 (2) 419/999 (3) 417/990 (4) 423/999 Solution: Let x = 0.423423423…. 1000x = 423+ 0.423423423….... View Article
The First Term Of A Gp Whose Second Term Is 2 And Sum To Infinity Is 8 Will Be
(1) 6 (2) 3 (3) 4 (4) 1 Solution: Given the second term of GP = 2 ar = 2... View Article
The Sum Can Be Found Of An Infinite Gp Whose Common Ratio Is R
(1) For all values of r (2) For only positive value of r (3) Only for 0 < r <... View Article
The Two Geometric Means Between The Number 1 And 64 Are
(1) 1 and 64 (2) 4 and 16 (3) 2 and 16 (4) 8 and 16 Solution: Let 1, G1,... View Article
The Product Of Three Geometric Means Between 4 And 1 By 4 Will Be
(1) 4 (2) 2 (3) -1 (4) 1 Solution: Let 4, G1, G2, G3, 1/4 be the series. Here a... View Article
The Gm Of Roots Of The Equation X2 18x 9 0 Is
(1) 3 (2) 4 (3) 2 (4) 1 Solution: Given equation x2-18x+9 = 0 Let α, β are the roots... View Article
If Five Gms Are Inserted Between 486 And 2 By 3 Then The Fourth Gm Will Be
(1) 4 (2) 6 (3) 12 (4) -6 Solution: Let the five GM’s be G1, G2, G3, G4, and G5.... View Article
If A B C Are In Ap Then 1 By Bc 1 By Ac 1 By Ab Will Be In
(1) A.P (2) G.P (3) H.P (4) None of these Solution: Given a, b, c are in AP. If we... View Article
The Product 32 32 1 By 6 32 1 By 36 Infinity Is
(1) 16 (2) 32 (3) 64 (4) 0 Solution: 32(32)1/6 (32)1/36 ….∞ = 321 + 1/6 +…∞ Here the power... View Article
The Sum Of A Gp With Common Ratio 3 Is 364 And Last Term Is 243 Then The Number Of Terms Is
(1) 6 (2) 5 (3) 4 (4) 10 Solution: Given r = 3 Last term, arn-1 = 243 a(3n-1) =... View Article
