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C1 C0 2c2 C1 3c3 C2 Ncn Cn 1 Is Equal To

\(\begin{array}{l}\frac{C_1}{C_0}+2\frac{C_2}{C_1}+3\frac{C_3}{C_2}+….+n\frac{C_n}{C_{n-1}}\end{array} \) is equal to (1) n(n-1)/2 (2) n(n+1)/2 (3) (n+1)(n+2)/2 (4) None of these Answer: (2) n(n+1)/2 Solution: \(\begin{array}{l}\frac{C_1}{C_0}+2\frac{C_2}{C_1}+3\frac{C_3}{C_2}+….+n\frac{C_n}{C_{n-1}}\end{array}... View Article