If N2c8 N 2p4 57 16 Then N Is Equal To
If n+2C8 : n –2P4 = 57/16, then n is equal to: 1) 19 2) 2 3) 20 4) 5... View Article
If n+2C8 : n –2P4 = 57/16, then n is equal to: 1) 19 2) 2 3) 20 4) 5... View Article
In a cricket championship, there are 36 matches. The number of teams, if each plays 1 match with other are... View Article
From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in... View Article
If n –1C3 + n –1C4 > nC3 , then n is just greater than: 1) 5 2) 6 3)... View Article
From 12 books, the difference between number of ways a selection of 5 books when one specified book is always... View Article
There are two urns. Urn A has 3 distinct red balls and urn B has 9 distinct blue balls. From... View Article
A student is allowed to select at most n books from a collection of (2 n+ 1)books. If the total... View Article
A teacher takes 3 children from her class to the zoo at a time as often as she can, but... View Article
Statement I The number of ways distributing 10, identical balls in 4 distinct boxes such that no box is empty,... View Article
If χ = {11, 2, 3, 4, 5}, then the number of different ordered pairs (Y, Z) that can formed... View Article
Let an, denote the number of all n-digit positive integers formed by the digits 0, 1 or both such that... View Article
Let an, denote the number of all n-digit positive integers formed by the digits 0, 1 or both such that... View Article
The total number of ways in which 5 balls of different colors can be distributed among 3 persons so that... View Article
Answer: (1) 64 Given White balls = 2 Black balls = 3 Red balls = 4 Solution: Selection of 3... View Article
A student is to answer 10 out of 13 questions in an examination such that he must choose at least... View Article
1) 256 2) 220 3) 219 4) 211 Answer: (3) 219 Solution: Total number of elements = 2 x 4... View Article
Determine n, If 2nC2 : nC2 : 9 : 2 1) 5 2) 4 3) 3 4) 2 Answer: (1)... View Article
Find nC21, If nC10 = nC11 1) 1 2) 0 3) 11 4) 10 Answer: (1) 1 Solution: Given, nC10... View Article
1) 11 2) 5 3) 7 4) 9 Answer: (2) 5 Solution: We can write, 11Cn = 11!/n!(11-n)! Now as... View Article
\(\begin{array}{l}\frac{C_1}{C_0}+2\frac{C_2}{C_1}+3\frac{C_3}{C_2}+….+n\frac{C_n}{C_{n-1}}\end{array} \) is equal to (1) n(n-1)/2 (2) n(n+1)/2 (3) (n+1)(n+2)/2 (4) None of these Answer: (2) n(n+1)/2 Solution: \(\begin{array}{l}\frac{C_1}{C_0}+2\frac{C_2}{C_1}+3\frac{C_3}{C_2}+….+n\frac{C_n}{C_{n-1}}\end{array}... View Article