(A) 1:3 (B) 2:1 (C) 2:3 (D) 3:1 The Correct Answer is (B) 2:1. Solution: Balmer series → Visible →... View Article
(A) Both assertion and reason are false. (B) Assertion is true, but the reason is false. (C) Both assertion and... View Article
(A) Both assertion and reason are false. (B) Assertion is true, but the reason is false. (C) Both assertion and... View Article
(A) NaPO4 (B) Na2PO4 (C) Na3PO4 (D) Na4PO4 The Correct Answer is (C) Na3PO4 Solution: The empirical formula is to... View Article
(A) Dilution (B) Ionisation (C) Neutralisation (D) Both (A) and (B). The Correct Answer is (D) Both (A) and (B).... View Article
(A) 8 (B) 16 (C) 24 (D) 32 The Correct Answer is (A) 8. Solution: The total number of stereoisomers... View Article
(A) 34.5 (B) 68.4 (C) 136.8 (D) 171.2 The Correct Answer is (B) 68.4 Solution: Given: 5% solution of cane... View Article
(A) 20% (B) 39.8% (C) 40.0% (D) 48.0% The Correct Answer is (A) 20% Solution: Percentage of Br = \(\begin{array}{l}... View Article
(A) 4 ml (B) 10 ml (C) 20 ml (D) 40 ml The Correct Answer is (D) 40 ml. Solution:... View Article
(A) CHO (B) CH2O (C) CH3O (D) CH4O The Correct Answer is (C) CH3O Solution: The empirical formula is to... View Article
(A) To dissolve Ag2S (B) To dissolve AgCN (C) To remove silver halides (D) To decompose Na2S and NaCN The... View Article
(A) MnO-4 = 2,C2O2-4 = 16, H+ = 5 (B) MnO-4 = 2,C2O2-4 = 5, H+ = 16 (C) MnO-4... View Article
(A) 65 (B) 70 (C) 100 (D) 140 The Correct Answer is (B) 70 Solution: The Atomic mass of nitrogen... View Article
(A) Assertion is true, but the reason is false. (B) Both assertion and reason are false. (C) Both assertion and... View Article
(A) \(\begin{array}{l} \rho _{1} + \rho _{2} \end{array} \) (B)\(\begin{array}{l} 2\rho _{1} + 2\rho _{2} \end{array} \) (C)\(\begin{array}{l} \frac{\rho _{1}... View Article
Solution: The molecular formula of hydrocarbons is C5H10, which satisfies the general formula CnH2n. This suggests that the hydrocarbon can... View Article
i) △DAP≅△EBP Given that, ∠EPA=∠DPB Now, ∠EPA+∠DPE=∠DPB+∠DPE Hence, ∠DPA=∠EPB Now, by using the triangles EBP and DAP, ∠EBP=∠DAP (given) Since... View Article
Consider ABCD is a square lawn whose side is 58m. Also, AED and BFC are the two circular ends Therefore,... View Article
(i) ∠DAC=∠BCA Since, ABC is an isosceles triangle, Let, ∠ABC=∠BCA=y Also, given that ∠QAD=∠DAC = x (Let) By using the... View Article
According to the definition of zeroes of a polynomial, the real number “k” is said to be a zero of... View Article