Round 15.5 to the nearest integer.
15.5 to the nearest integer is 16. The number 15.5 has two parts, such as the integer part and the... View Article
15.5 to the nearest integer is 16. The number 15.5 has two parts, such as the integer part and the... View Article
(a) Σ Cot A/2 (b) Σ Cot A/2 Cot B/2 (c) Σ tan A/2 (d) Π tan A/2 Solution: Correct... View Article
The value of root 49 is 7. As we know the square root of 49 is a number which when... View Article
a) b) c) d) Solution: Option d) describes the subsequent variation of the magnitude of current density j(t) at any... View Article
Solution: Solid angle is defined as a three dimensional angle subtended by any part of a spherical surface of unit... View Article
a) AC is in tension with force of 1000 N b) AC is in tension with force of 4000/3 N... View Article
Solution: We know that \(\begin{array}{l}F_{G1}=F_{N1} and F_{G1}=F_{N1} and F_{G2}=F_{N2}\end{array} \) \(\begin{array}{l}\Sigma F_{x} = F – F_{1}-F_{2}=m_{T}a\end{array} \) \(\begin{array}{l}\Sigma F_{x} =... View Article
a) b) c) d) Solution: The phase relationship between current and voltage in a pure resistive circuit is best represented by... View Article
Solution For body C, T1-g=1*g Hence, T1=2g For body B, T2-T1-3g=2*3g T2=11g For body A, T3-T2-6g=3*6g T2=33g Instantaneous change in... View Article
a) b) c) d) Solution: Option a) is the correct answer since the values match with the value of screw... View Article
Einstein’s photoelectric equation for the work function of metal is given by : \(\begin{array}{l}\phi = \frac{hc}{\lambda}\end{array} \) \(\begin{array}{l}\phi = \frac{6.6*10^{-34}*3*10^{8}}{4000*10^{-10}}... View Article
a) The density continuously increases from left to right. b) The density decreases from left to right up to the... View Article
a) b) c) d) Solution: Option d) is the right answer. This graph explains that when the particle is moving... View Article
a) b) c) d) Solution: C) is the right option. Applying Kirchoff’s law in the circuit we get, \(\begin{array}{l}I_{1}+I_{2}+I_{3}=0\end{array} \) \(\begin{array}{l}\frac{V-E}{r}+\frac{V-E}{r}+\frac{V-E}{r}=0\end{array}... View Article
A. a_{1}=6a_{2} B. a_{1}=3a_{2} C. a_{2}=6a_{1} D. a_{2}=3a_{1} Solution: C. a_{2}=6a_{1}
a) RCln3 b) RC/2 ln3 c) 2RCln2 d) RC/3 ln3 Solution:a) RCln3
a) AND b) OR c) NOR d) NAND Solution: c) NOR
Given VBE = 0.7 V, S=0.7V, and I=2K\Omega I_{E}= \frac{4.3}{2*10^{3}} = 3.7 mA
a) ¼ b) ⅛ c) 1 d) 8 Solution: b) ⅛
Solution: We know that \(\begin{array}{l}F=\frac{GM}{r^{2}}\end{array} \) If r\geq R \(\begin{array}{l}\frac{F1}{F2}=\frac{r2^{2}}{r1^{2}}\end{array} \) When r1≥R, r2≥R Again \(\begin{array}{l}F=\frac{GMr}{R^{2}}\end{array} \) When r≥R Force... View Article