the correct order of bond lengths for c–c bonds in benzene, ethyne, ethene and ethane is
One sigma and one pi bond are found in alkene bonds. One sigma and one pi bond are also found... View Article
One sigma and one pi bond are found in alkene bonds. One sigma and one pi bond are also found... View Article
△Q = nCp△T (Cp)m = [1 x (5R/2) + (1x7R/2)]/2 = 12R/4 = 3R △Q = 2 x 3R x... View Article
Molecular Mass of CH4=16 Moles of CH4 = x/16 Molecular Mass of O2=32 Moles of O2 = x/32 Total moles... View Article
SO2 and Cl2 pairs has bleaching action. Sulfur dioxide and chlorine are both effective bleaching agents. Chlorine’s bleaching action is... View Article
There are 8 alcohol possible for c5h12o molecule. They are 1-pentanol 2-pentanol 3-pentanol 2-methylbutan-1-ol 2-methylbutan-2-ol 3-methylbutan-2-ol 3-methylbutan-1-ol 2,2-dimethylpropanol A haloform... View Article
1st half- Life → 50% decay 2nd half- Life → 75% decay The half-life period of the radioactive element, if... View Article
We can say that at equilibrium, the rate of dissolution is the forward reaction and the rate of crystallisation is... View Article
According to the law of definite proportion, a given compound always has the same proportion of constituents by weight. Case... View Article
For Cu(OH)2, the expression of solubility product is: Ksp = [Cu2+][OH-]2 = (s)(2s)2 = 4s3 Substitute Ksp = 1.6 ×... View Article
Magnesite − MgCO3 Siderite − FeCO3 are the correct set of carbonate ore.
Flocculation, also known as coagulation is the process of precipitation of a colloidal solution by the addition of the excess... View Article
The relation between lead nitrate and potassium iodide is an example of precipitation reaction. Pb(No3)2 + 2KI ⟶ PbI2 +... View Article
t=0 activity is N0 then after time t the activity is given as 100=1600×(1/2)^n so n=4 n=4 and t=8s we... View Article
Mole fraction of NO2=2x/(1−x+2x)=2x/(x+1)=1/2 solving, we get 4x=x+1 3x=1 x=1/3 =(4/9)/(2/3)=4X3/9X2=2/3 Therefore, 2/3 is the answer.
W = −1×8.314×300×ln 20/10 W = −2494.2×(ln2−ln1) = −1728.8J = −1.73 kJ From first law of thermodynamics, ΔU=ΔH+W Since temperature... View Article
Smaller the gold number, greater is the protective power. 0.25>0.1>5>15
For Oxygen , no of moles n1=2 , no. Of degree of freedom per molecule, f1=5 For Argon, no.of moles... View Article
Any metal will reduce the oxide of other metals above it on the Ellingham diagram because the free energy difference... View Article
In neutralisation of 1 mole of NaOH by 1 mole HCl, heat evolved =57.3kJ To neutralise 0.04 mole of NaOH... View Article
If the sum of all powers elevated to the concentration is zero, a reaction is said to be zero order,... View Article